1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leonid [27]
3 years ago
12

Brianna is a multimedia specialist who works for a large fast food chain. What task

Computers and Technology
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

Recording and publishing training videos for new employees

Explanation:

Multimedia specialists design and create IT-based multimedia products such as websites, DVDs, and computer games that combine text with sounds, pictures, graphics, video-clips, virtual reality and digital animation

You might be interested in
Design a class that has an array of floating-point numbers. The constructor should accept an integer argument and dynamically al
attashe74 [19]

Answer:

See explaination for the code

Explanation:

Here is the code

class NumberArray

{

private:

float *aptr; // Pointer to the array

int arraySize; // Holds the array size

float max,min,avg;

public:

NumberArray(int); // Constructor

~NumberArray(); // Destructor

int size() const // Returns the array size

{ return arraySize; }

void storeNumber(float num,int ele);

float retrieveNumber(int ele);

float getHighest();

float getLowest();

float getAverage();

};

//*******************************************************

// Constructor for IntArray class. Sets the size of the *

// array and allocates memory for it. *

//*******************************************************

NumberArray::NumberArray(int s)

{

arraySize = s;

aptr = new float [s];

for (int count = 0; count < arraySize; count++)

*(aptr + count) = 0;

}

//******************************************************

// Destructor for IntArray class. *

//******************************************************

NumberArray::~NumberArray()

{

if (arraySize > 0)

delete [] aptr;

}

void NumberArray::storeNumber(float num,int ele)

{

if(ele<arraySize)

*(aptr+ele)=num;

}

float NumberArray::retrieveNumber(int ele)

{

return *(aptr+ele);

}

float NumberArray::getHighest()

{

float high=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(high<*(aptr+i))

high=*(aptr+i);

return high;

}

float NumberArray::getLowest()

{

float low=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(low>*(aptr+i))

low=*(aptr+i);

return low;

}

float NumberArray:: getAverage()

{

float ag=0;

for(int i=1;i<arraySize;i++)

ag+=*(aptr+i);

ag=ag/arraySize;

return ag;

}

//Header file section

#include <iostream>

using namespace std;

int main()

{

const int SIZE = 10; // Array size

// Define an IntArray with 10 elements.

NumberArray table(SIZE);

//function call to store values

table.storeNumber(1,0);

table.storeNumber(3,1);

table.storeNumber(7,2);

table.storeNumber(2,3);

//display values

cout<<"Highest value:"<<table.getHighest()<<endl;

cout<<"Lowest Value:"<<table.getLowest()<<endl;

cout<<"Average:"<<table.getAverage()<<endl;

///pause system for a while

system("pause");

return 0;

}

6 0
3 years ago
Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
leonid [27]

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = \mathbf{\bigg ( ( 42 -  (no. \ of \  failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \  comparisons) ) \bigg ) }

Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )

Total number of character comparison = 41 + 2

Total number of character comparison = 43

3 0
3 years ago
What could prevent ping or traceroute responses from reaching the originating device beside network connectivity issues?
zysi [14]
Many admins set their firewalls to drop echo-request packets to prevent their networks from being mapped via "Ping Sweeps".

A remote possibility is that there's too many hops between the source and target and the packet's TTL expires.
3 0
4 years ago
Ask the user to input their grade percentage (e.g. the use will enter 98 if they had an overall grade of 98% in their course) fo
Airida [17]

Answer:

In Python

def getpointValue(subject):

   if subject >= 75:        point = 4; grade = 'A'

   elif subject >= 60:        point = 3; grade ='B'

   elif point >= 50:        point = 2; grade = 'C'

   elif point >= 40:        point = 1; grade = 'D'

   else:        point = 0; grade = 'F'

   return point,grade

subjects= ["Accounting","Marketing","Economics","MIS"]

acct = int(input(subjects[0]+": "))

mkt = int(input(subjects[1]+": "))

eco = int(input(subjects[2]+": "))

mis = int(input(subjects[3]+": "))

acctgrade = getpointValue(acct)

print(subjects[0]+" Grade: "+str(acctgrade[1]))

mktgrade = getpointValue(mkt)

print(subjects[1]+" Grade: "+str(mktgrade[1]))

ecograde = getpointValue(eco)

print(subjects[2]+" Grade: "+str(ecograde[1]))

misgrade = getpointValue(mis)

print(subjects[3]+" Grade: "+str(misgrade[1]))

totalpoint = (acctgrade[0] + mktgrade[0] + ecograde[0] + misgrade[0]) * 3

gpa = totalpoint/12

print("GPA: "+str(gpa))

Explanation:

<em>The solution I provided uses a function to return the letter grade and the point of each subject</em>

<em>I've added the explanation as an attachment where I used comment to explain difficult lines</em>

<em />

Download txt
6 0
3 years ago
What is the rotation used for the picture in Fig 17
mihalych1998 [28]

Answer:

hi, where is the picture

8 0
2 years ago
Other questions:
  • Which agricultural CTSO has programs for middle-school and high-school students, as well as college students?
    13·2 answers
  • Discuss in detail why you need to use a write blocker (either hardware or software) in your examinations, whether for a criminal
    6·1 answer
  • What is data anayltics
    5·1 answer
  • Select four programs that make up system software.Select four programs that make up system software.
    8·1 answer
  • nswer the following questions concerning chapter 1:1.1 Which pair of layers are NOT peer layers?a.Transport layer in the sender
    9·1 answer
  • In Microsoft word you can access the blank command from the mini toolbar
    7·1 answer
  • If Word finds a potential error in a document, a red, green, or blue wavy underline flags the problem.
    14·1 answer
  • What was the first portable computer called and who made it?
    9·1 answer
  • JUST NEED TO KNOW WHO ALL DOSE EDGINUITY
    12·2 answers
  • Attackers will sometimes put malware on USB drives and leave them in parking lots
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!