Shuffle (A[1..m], B[1..n], C[1..m+n]):
Shuf[0, 0] ← True
for j ← 1 to n
Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])
for i ← 1 to n
Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])
for j ← 1 to n
Shuf[i, j] ← False
if A[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]
if B[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]
return Shuf[m, n]
The algorithm runs in O(mn) time.
This for loop will output:
0
2
4
The range(3) is all the integers between 0 inclusive and 3 exclusive. 0, 1, 2.
Every iterations through the for loop, we multiply the value of each number by 2 and print it to the console.
0 * 2 = 0
1 * 2 = 2
2 * 2 = 4
I hope this helps.
The answer would be D) because they want the best of the best
Answer:
That would be a result of a bad internet connection of an ADgaurd is blocking the site.
Explanation:
Answer:
Option D is the correct answer to this question.
Explanation:
The redundancy in the internet routing is most important in many terms:
- It is true that if a single router on a network breaks, the entire network fails because the redundancy makes the network strong to receive and send the packets from source to the destination.
- Breaking of any single router can results to the entire failure of network and it fails to send the packets to the destination.
- Redundancy helps in making an internet more reliable and send or forward the data packets from the source to destination.
