Answer:
40%
Explanation:
Remember that guanine always pairs with cytosine, and thymine always pairs with adenine. That means that any time there is a guanine, there is always a cytosine.
If there are 10% guanines, then there are 10% cytosines. That means the total of guanines and cytosines is 20%.
The other 2 bases (thymine and adenine) have to make up the rest of the bases. That means they have to make up 100-20 = 80%.
Again, there will be equal amounts of thymine and adenine, so 80%/2 = 40%.
Answer:
ans is c is correct pls mark me as brainlist pls
<u>The illegal wildlife trade </u>or <u>wildlife trafficking</u> is the commercial process that involves the trade of non-domestic species (animals or plants), or in some cases certain parts of individuals. These species are rare and endangered and thus this practice is harmful and represents an increasing dangers of extinction.
This practice is highly illegal, but unfortunately, at the same time, due to the rarity of the species highly profitable. Efforts are made globally to stop this practice and to avoid the extinction of many endangered species.
Mass is what you would measure in kilograms
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
