Answer:
54 I think
Step-by-step explanation:
I just did 15 divided by 9 and got 5/3 and then did 90 divided by 5/3 and got 54
Answer:
<u>x = 6</u>
Step-by-step explanation:
Taking the sides in proportion :
- EB/DC = AB/AC
- 8/24 = -3 + 2x/27
- 1/3 = -3 + 2x/27
- 3(-3 + 2x) = 27
- -9 + 6x = 27
- 6x = 36
- <u>x = 6</u>
Answer:
AB = 8.857 cm
Step-by-step explanation:
Here, we are given a <em>right angle</em>
in which we have the following things:

Side <em>BC </em>is the hypotenuse here.
We have to find the side <em>AB</em>.
Trigonometric functions can be helpful to find the value of Side AB here.
Calculating
:
Sum of all the angles in
is
.

We know that <em>cosine </em>of an angle is:

So, side AB = 8.857 cm
.
The y int is where the line crosses the y axis ...so ur y int is 3 or (0,3).
ur slope...start at the y int (0,3)....and if u come down 3, and go to the right 2, and down 3, and to the right 2 u are landing on ur line. So ur slope is -3/2
Hi there! You have to remember these 6 basic Trigonometric Ratios which are:
- sine (sin) = opposite/hypotenuse
- cosine (cos) = adjacent/hypotenuse
- tangent (tan) = opposite/adjacent
- cosecant (cosec/csc) = hypotenuse/opposite
- secant (sec) = hypotenuse/adjacent
- cotangent (cot) = adjacent/opposite
- cosecant is the reciprocal of sine
- secant is the reciprocal of cosine
- cotangent is the reciprocal of tangent
Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.
What we have now are:
- Trigonometric Ratio
- Adjacent = 12
- Opposite = 10
Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!
Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite
Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.
- 10²+12² = c²
- 100+144 = c²
- 244 = c²
Thus, the hypotenuse is:

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:
- cosine (cosθ) = adjacent/hypotenuse = 12/(2√61) = 6/√61 = <u>(6√61) / 61</u>
- sine (sinθ) = opposite/hypotenuse = 10/(2√61) = 5/√61 = <u>(5√61) / 61</u>
- cosecant (cscθ) is reciprocal of sine (sinθ). Hence, cscθ = (2√61/10) = <u>√61/5</u>
- secant (secθ) is reciprocal of cosine (cosθ). Hence, secθ = (2√61)/12 = <u>√</u><u>61</u><u>/</u><u>6</u>
Questions can be asked through comment.
Furthermore, we can use Trigonometric Identity to find the hypotenuse instead of Pythagorean Theorem.
Hope this helps, and Happy Learning! :)