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LUCKY_DIMON [66]
3 years ago
10

What numbers when multiplied gives me -6 and when added 5.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

The answer is -11

Step-by-step explanation:

-11 + 5 = -6

Mark as brainliest ^-^

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Given the function f(x)=|x|,describe the transformation lys to f(x)=|x-2|+5
earnstyle [38]
C is the correct answer
Since it says x-2 which is a horizontal translation and everything horizontal says you say the other way around. So left to you go right 2

Hope that helps 
5 0
3 years ago
Could someone help and explain their answer? (NO LINKS!)<br> Thanks!
Nonamiya [84]

Answer:

5

Step-by-step explanation:

To find the prime factorization of a number, start by dividing the number by each prime number that you can divide by as many times as possible, starting with the smallest prime number and moving up. Then move on to the next prime number. The last division must give a quotient of 1. Then the prime factorization is the product of all the prime factors you divided the number by.

Here's how you use this method with 180.

Here are the first 10 prime numbers:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29

Start by trying to divide by 2. 180 is divisible by 2.

180/2 = 90       90 is divisible by 2.

90/2 = 45         45 is not divisible by 2, so now try 3.

45/3 = 15          15 is divisible by 3.

15/3 = 5            5 is prime, so it is divisible by 5.

5/5 = 1              The divisors in bold are the prime factors of 180.

180 = 2 × 2 × 3 × 3 × 5

180 = 2² × 3² × 5

Answer: 5

3 0
3 years ago
Read 2 more answers
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
Jessie's bus ride to school is 5 minutes more then 2/3 the time roberts bus ride. if jessie's time riding the bus is y and rober
Rainbow [258]
X=2/3y because you want to know what roberts time is
7 0
3 years ago
Find the missing length. The triangles are similar.
hodyreva [135]

Answer:

182

Step-by-step explanation:

First, we can say that ∠ACB and ∠BCF are opposite angles because they are not next to each other and are formed by intersecting lines. Therefore, ∠ACB = ∠BCF

Next, angles correspond with the side opposite of it. This means that, for example, ∠ACB corresponds with line AB and ∠BCF corresponds with line BF. Because ∠ACB and ∠BCF are equal and the triangles are similar, we can say that their corresponding sides have a ratio with each other. Similarly, ∠CAB corresponds to CB, ∠ABC corresponds to AC, ∠CWV corresponds to CV, and ∠CVW corresponds to CB.

Because the triangle CVW is isosceles, we can say that the angles whose corresponding sides are equal are equal as well, so ∠CAB = ∠ABC and ∠CVW = ∠CVW. Next, because ∠ACB and ∠BCF are equal and correspond to each other, and the other two angles in each triangle are equal to each other, we can say that the other two angles must be equal. Another way of putting this is like this:

Say that x = ∠CAB. Then,

∠CAB + ∠ABC + ∠ACB = 180

x + x + ∠ACB = 180

2x + ∠ACB = 180

subtract ∠ACB from both sides

180 - ∠ACB = 2x

Similarly, if y = ∠CWV,

180 - ∠WCV = 2y. Therefore, 2y=2x and y=x, so ∠CAB = ∠ABC = ∠CWV = ∠CVW.

Given this, we can say that sides CV and CW correspond with BC and AC. This means that the ratio between, for example, CV and BC is equal to the ratio between CW and AC. Therefore,

CV/BC = CW/AC

84/182 = 84/?

Filling in the blank, 84/182 is equal to 84/182, so ? = 182

8 0
3 years ago
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