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quester [9]
3 years ago
14

Which of the following is a radical equation? x + StartRoot 5 EndRoot = 12 x squared = 16 3 + x StartRoot 7 EndRoot = 13 7 Start

Root x EndRoot = 14

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

x = 3

Step-by-step explanation:

(8x-8)^{3/2}=64

Multiply both sides by the exponent 2/3.

8x - 8 = 64^{2/3}

Solve for the exponent.

8x-8=16

Add 8 to both sides.

8x = 16+8

8x=24

Divide 8 into both sides.

x=24/8

x=3

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JulsSmile [24]
I believe it’s 6

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4 0
3 years ago
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Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
4 years ago
Ann ran a 5 kilometer race in 45 minutes. Write an inequality
guapka [62]

Answer:

ghgyeryeughheyyrgjehrgb ehgryeurghekdrdrg dhgidrg

6 0
3 years ago
An experiment was conducted to test the effect of a new cholesterol medicine. Fifteen people were treated with medicine X and 15
gtnhenbr [62]

Considering the hypothesis tested and the p-value of the test, the correct option is given by:

There is sufficient evidence that there is a difference in mean cholesterol level when using medicine X and medicine Y.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference between the cholesterol levels, that is:

H₀:Hₓ-H

At the alternative hypothesis it is tested if there is a difference, hence:

H₀:Hₓ-H≠0

The p-value is of 0.003 < 0.01, hence we reject the null hypothesis and conclude that there has was a difference, hence the correct option is given by:

There is sufficient evidence that there is a difference in mean cholesterol level when using medicine X and medicine Y.

More can be learned about hypothesis tests at brainly.com/question/26454209

#SPJ1

6 0
2 years ago
Please some one help me.​
vagabundo [1.1K]

Answer:

-11

Step-by-step explanation:

You need to take the absolute value of 12-15 which would be 3. Then take -8-3 which would be -11

3 0
3 years ago
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