Question

What is the value of F in this equation F^2=9/49

Answer 1

Answer:

$\sqrt{f {}^{2} } = \sqrt{ \frac{9}{49} }$

$f = \frac{ \sqrt{9} }{ \sqrt{49} }$

$f = \frac{3}{7}$ or -3/7

Answer 2

Answer:

$f=-\frac{3}{7},\frac{3}{7}$

Step-by-step explanation:

$f^2=\frac{9}{49}$

Square root both sides of the equation:

$\sqrt{f^2} =\sqrt{\frac{9}{49} }$

The square root of $f^2$ is $f$, so let's rewrite the equation:

$f=\sqrt{\frac{9}{49} }$

Now, we can make this easier on ourselves by noticing that both the numerator and denominator of the fraction are square numbers, so rewrite the equation:

$f=\frac{\sqrt{9} }{\sqrt{49}}$

Find the square root of 9 (-3 & 3), and the square root of 49 (-7 & 7). Due to the possibility of the positive or negative solution, there will be two:

$f=-\frac{3}{7} ,\frac{3}{7}$