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Serhud [2]
3 years ago
9

90 POINTS PLEASE HELP

Mathematics
1 answer:
zimovet [89]3 years ago
5 0

Formula

Volume = A_base * height

Solution

Synthetic Division always changes signs of the divisor. Also you add whereas in long division you subtract.

-2   ||  2   +    9  -  8   - 36

                   -4   -10     36

      ===================

          2       5     -18    0

You can eliminate A and B. You are never left with the same power at the beginning when you do a division.

What you are left with is

A_Base = 2x^2 + 5x - 18

Answer: D

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Around the 4-2. 7+6=13•2=26 ;)
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What is the slope of the line that passes through the points (-3, 5) and (1, 15)
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Someone answer 1-8 please! (Please do help!)<br> QUESTION: Find each quotient.
Zinaida [17]
Sorry, but I generally respond to only 1 or 2 problems when someone gives me a long list of homework.  It would take you just a little longer to post one problem at a time.
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Let's look at #5:     75 / (-1/5)   is the same as  -------- = 75 * ------ = ---------                                                                                         -1                -1         1
                                                                              ---
                                                                                5

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6 0
3 years ago
Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
When making a book cover, Anwar adds an additional 20 square inches to the surface area to allow for overlap. How many square in
e-lub [12.9K]

Answer:

234 square inches

Step-by-step explanation:

We are given that

Length of book, l=11 in

Width of book, w=8 in

Height of book, h=1in

Additional area required to overlap=20 square inches

We have to find how many square inches of paper to make  cover of one book.

We know that surface area of cuboid

S=2(lb+bh+hl)

Using the formula

Surface area of book

S=2(11\times 8+8\times 1+1\times 11)

S=214 in^2

Total paper used to make cover of one book

=Surface area of book +additional surface area

=214+20

=234in^2

Hence, Anwar will use paper to make cover of one book=234 square inches

3 0
3 years ago
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