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bearhunter [10]
2 years ago
12

An item is regularly priced at 25. It is on sale for 80% off the regular price. What is the sale price?

Mathematics
2 answers:
Burka [1]2 years ago
7 0

<u>answer</u>:

sale price: $5

<u>explanation</u>:

total price is always 100%

sale price is 80% off,

sale price: 100% - 80% = 20%

<u>solve</u>:

→ 20% * $25

→ $5

Marina86 [1]2 years ago
6 0

Answer:

$5

Step-by-step explanation:

25\times(1-80)\\25\times(1-0.8)

<u><em>Calculate the sum or difference</em></u>

<u><em /></u>25\times0.2

<u><em>Calculate the product or quotient</em></u>

<u><em /></u>5

<em>I hope this helps you</em>

<em>:)</em>

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Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0
3 years ago
What is the value of (–4)–3?
son4ous [18]
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The general form for a linear equation is given as: y = a + bx. In the regression equation, b is called the ______.
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Answer:

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Step-by-step explanation:

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3 years ago
Which table shows input and output values that represent a linear function?
shepuryov [24]

Answer:

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Step-by-step explanation:

In order for it to be a linear relationship, the change in the x values and y values (f(x)) needs to be consistent.

In every table, the x values change the same, so we can focus on the y values.  

Notice in table A, the f(x) values go down consistently by 10 for every change in x.  

All of the other tables are not consistent.  

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4 0
3 years ago
A square grassy field is watered by 4 sprinklers. The sprinklers spray water in a circular pattern, as shown above. If the field
enot [183]
The answer is (3600 - 900π) ft²

Step 1. Find the radius r of circles.
Step 2. Find the area of the portion of the field that will be watered by the sprinklers (A1)
Step 3. Find the total area of the field (A2)
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A)

Step 1. Find the radius r of circles
r = ?
According to the image, radius of a square is one fourth of the field side length:
r = s/4
s = 60 ft
r = 60/4 = 15 ft

Step 2. Find the area of the portion of the field that will be watered by the sprinklers.
The area of the field that will be watered by the sprinklers (A1) is actually total area of 4 circles with radius 15 ft.
Since the area of a circle is π r², then A1 is:
A1 = 4 * π r² = 4 * π * 15² = 900π ft²

Step 3. Find the total area of the field (A2)
The field is actually a square with side s = 60 ft.
A2 = s² = 60² = 3600 ft²

Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A).
To get the area of the portion of the field that will not be watered by the sprinklers (A) we need to subtract the area of 4 circles from the total area:
A = A2 - A1
A = (3600 - 900π) ft²
5 0
3 years ago
Read 2 more answers
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