Jenna is having a sidewalk sale. She pays $12 for a

What factors multiply to -80 and add to 6

forsale [732]

80 = -1(80), -2(40), -4(20), -5(4),

Total answers include: -81, 79, -42, 16, -9, and 1.

None of them add up to 6!

Are you doing polynomial equations?

If so, you can solve it the hard way.

x^2 + 6x -80 = 0

(x^2 + 6x + 9) - 80 = 9

(x+3)^2 = 89

(x+3) = 9.43

x = 6.43

If you're not doing those then I'm afraid your question has no answer.

Hope that helps!

7 0

3 years ago

Plzz help me to solve this qns please

tatiyna

9514 1404 393

Answer:

₹14000

Step-by-step explanation:

Let c represent the cost price, and m represent the marked price.

c × (1 +40%) = m

m × (1 -15%) - c = ₹1900

Using the first expression for m, the second equation becomes ...

1.40c×0.85 -c = ₹1900

0.19c = ₹1900

c = ₹1900/0.19 = ₹10000

Then the marked price was ...

m = 1.40c = 1.40×₹10000 = ₹14000

The marked price was ₹14000.

_____

The selling price was ₹11900.

7 0

3 years ago

mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for

frez [133]

mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .

<u>Step-by-step explanation:</u>

Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest . Let's find out:

Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.

⇒ $\frac{8000(12)}{100}(x) +\frac{2000(8)}{100}(x) =5600$

⇒ $\frac{8000(12)+2000(8)}{100}(x) =5600$

⇒ $(80(12)+20(8))(x) =5600$

⇒ $(960+160)(x) =5600$

⇒ $(1020)(x) =5600$

⇒ $x =\frac{5600}{1020}$

⇒ $x =5.5$

Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .

6 0

3 years ago

Expanded form for 48,243. (

Dima020 [189]

(4*10,000)+(8*1,000)+(2*100)+(4*10)+(3*1)

40,000+8,000+200+40+3=48,243

That is one way. You can also do this using exponential form!

Hope that helps

4 0

3 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago