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klasskru [66]
2 years ago
13

the rectangle shown has a perimeter of 56 cm and the given area. it's length is 8 more than three times it's width. write and so

lve a system of equations to find the dimensions of the rectangle.​

Mathematics
1 answer:
stiv31 [10]2 years ago
4 0

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

Assume width of rectangle be " x ", length = 3×width + 8 = 3x + 8 ~

Now, Perimeter of rectangle is :

\qquad \sf  \dashrightarrow \:2(l + w)  = 56

\qquad \sf  \dashrightarrow \:2(3x + 8 + x)  = 56

\qquad \sf  \dashrightarrow \:2(4x + 8)  = 56

\qquad \sf  \dashrightarrow \:4x + 8  = 56 \div 2

\qquad \sf  \dashrightarrow \:4x + 8  = 28

\qquad \sf  \dashrightarrow \:4x  = 28 - 8

\qquad \sf  \dashrightarrow \:x = 20\div 4

\qquad \sf  \dashrightarrow \:x =5 \: cm

Hence, width = x = 5 cm

\qquad \sf  \dashrightarrow \:l = 3w + 8

\qquad \sf  \dashrightarrow \:l = 3(5)+ 8

\qquad \sf  \dashrightarrow \:l = 15+ 8

\qquad \sf  \dashrightarrow \:l =23 \:cm

And, length = 26 cm

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