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Divide the numerator by the denominator and any remaining values go back above the denominator.
Example:
17 / 4 is an improper fraction. To turn it into a proper fraction we do 17 divided by 4.
17 / 4 is 4 with a remainder of 4. So we put the 4 on the outside and the 1 back above the denominator, which is 4.
It ends up looking like this:
Example:
17 / 4 is an improper fraction. To turn it into a proper fraction we do 17 divided by 4.
17 / 4 is 4 with a remainder of 4. So we put the 4 on the outside and the 1 back above the denominator, which is 4.
It ends up looking like this:
Answer:
There are two pairs of solutions: (2,7) and (-1,4)
Step-by-step explanation:
We will use substitution.
y = x^2 + 3
y = x +5
Since the second equation is equal to y, replace y in the first equation with the second equation.
y = x^2 + 3
x + 5 = x^2 + 3
Rearrange so that one side is equal to 0.
5 - 3 = x^2 - x
2 = x^2 - x
0 = x^2 - x - 2
You may use quadratic formula or any form of factoring to find the zeros (x values that make the equation equal to 0).
a = 1, b = -1, c = -2
Zeros = and
Zeros = 2 and -1
Now that you have your x values, plug them into the equations to find their corresponding y values.
y = x^2 + 3
y = (2)^2 + 3
y = 7
Pair #1: (2,7)
y = x^2 + 3
y = (-1)^2 + 3
y = 4
Pair #2: (-1,4)
Therefore, there are two pairs of solutions: (2,7) and (-1,4).