First 5 multiples of 7

Mathematics

1 answer:

GarryVolchara [31]3 years ago

7 0

Answer: 0, 7, 14, 21, and 28

Step-by-step explanation: To find the first 5 multiples of 7, multiply 7 by the first 5 whole numbers which I have done for you in the image attached.

To quickly review, the set of whole numbers are shown below.

{0, 1, 2, 3, 4, ...}

The numbers that I have highlighted in green will be your first 5 multiples.

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galina1969 [7]

Answer:

Step-by-step explanation:

We want to solve the equation:

$5\sin(2x)=3\cos(x)$

To do so, we can rewrite the equation.

Recall the double-angle for sine:

$\sin(2x)=2\sin(x)\cos(x)$

By substitution:

$5\left(2\sin(x)\cos(x)\right)=3\cos(x)$

Distribute:

$10\sin(x)\cos(x)=3\cos(x)$

We can subtract 3cos(x) from both sides:

$10\sin(x)\cos(x)-3\cos(x)=0$

And factor:

$\cos(x)\left(10\sin(x)-3\right)=0$

Hence, our answer is A.

*It is important to note that we should not divide both sides by cos(x) to acquire 10sin(x) = 3. This is because we need to find the values of x, and one or more may result in cos(x) = 0, and we cannot divide by 0. Hence, we should subtract and then factor.

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2 years ago

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Need help with this

anygoal [31]

Answer:

It's the 3rd option.

-p^6

Step-by-step explanation:

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3 years ago

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