Question

Find the missing term. Picture attached. Helppp

Answer 1

ANSWER

$\boxed {} = {x}^{158}$

EXPLANATION

The given expression is:

$({ {x}^{12} )}^{5} \times ({ {x}^{ - 2} )}^{9} \boxed {} = ({ {x}^{40} )}^{5}$

Use the property,

$({ {a}^{m} )}^{n} = { {a}^{mn} }$

$({ {x}^{60} )} \times ({x}^{ - 18} )\boxed {} = ({ {x}^{200} )}$

Use the property,

${a}^{m} \times {a}^{n} = {a}^{m + n}$

$({ {x}^{60 + - 18} )} \boxed {} = ({ {x}^{200} )}$

$({ {x}^{42} )} \boxed {} = ({ {x}^{200} )}$

Solve for box,

$\boxed {} = \frac{{x}^{200} }{{x}^{42}}$

Since they are dividing we subtract the exponents:

$\boxed {} = {x}^{200 - 42} = {x}^{158}$

Answer 2

Idk lol I’m just writing this for the 100% sorry