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galina1969 [7]
3 years ago
8

Find the missing term. Picture attached. Helppp

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0

ANSWER

\boxed {} =  {x}^{158}

EXPLANATION

The given expression is:

({ {x}^{12} )}^{5}  \times ({ {x}^{ - 2} )}^{9}  \boxed {} = ({ {x}^{40} )}^{5}

Use the property,

({ {a}^{m} )}^{n}  = { {a}^{mn} }

({ {x}^{60} )}  \times ({x}^{ - 18} )\boxed {} = ({ {x}^{200} )}

Use the property,

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

({ {x}^{60 +  - 18} )} \boxed {} = ({ {x}^{200} )}

({ {x}^{42} )} \boxed {} = ({ {x}^{200} )}

Solve for box,

\boxed {} =  \frac{{x}^{200} }{{x}^{42}}

Since they are dividing we subtract the exponents:

\boxed {} =  {x}^{200 - 42}  =  {x}^{158}

3241004551 [841]3 years ago
5 0

Idk lol I’m just writing this for the 100% sorry

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