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abruzzese [7]
3 years ago
14

title="(1+sin^{2} )cosx+(1+cos^{2} x)sinx=1=sin2x" alt="(1+sin^{2} )cosx+(1+cos^{2} x)sinx=1=sin2x" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
xeze [42]3 years ago
8 0

The answer is = 1 + sin x

Explanation

we need

a^2 - b^2 = (a+b) (a-b)

we use

cos^2 x + sin^2 x = 1

cos^2 x = 1 - sin^2 x = ( 1 + sin x) ( 1 - sin x )

therefore

cos ^2 x over 1 - sin x = 1+ sin x

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melisa1 [442]

Answer: 8/9

Step-by-step explanation:

First, we can find a common denomiator.

The least common multiple of 2, 9, and 6 is 18.

Therefore, the lcd is 18.

1/2 = 1/2 * (9/9) = 9/18

2/9 = 2/9 * (2/2) = 4/18

1/6 = 1/6 * (3/3) = 3/18

Therefore, 1/2 + 2/9 + 1/6 = 9/18 + 4/18 + 3/18.

We can add the numerators together.

= 16/18

Divide the nuumerator and denominator by 2:

= 8/9

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2 years ago
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Step-by-step explanation:

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6 0
3 years ago
Please help, picture attached.
lawyer [7]

Answer:

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hope that answers your question

Step-by-step explanation:

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