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garri49 [273]
3 years ago
10

N − 2/3 = 25 3/4 help now

Mathematics
1 answer:
Sav [38]3 years ago
5 0

Answer:

26 5/12

Step-by-step explanation:

n − 2/3 = 25 3/4                            Add 2/3 to both sides

n - 2/3 + 2/3 = 25 3/4 + 2/3         Combine

n = 25 3/4 + 2/3

Work with the fractions

3/4 + 2/3                                      The lowest common denominator is 12

(3*3)/(3*4) = 9 / 12

(2*4)/(3*4) = 8/ 12

9/12 + 8/12 = 17/12 = 1 5/12

Now you need to add 1 to 25

1 + 25 = 26

And add the fraction 5/12

The answer is 26 5/12

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12 different combinations because 4 times 3 equals 12.
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Someone help me on 1 pls
inessss [21]

Answer:

The answer is 140

Step-by-step explanation:

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3 years ago
Which is the constant term of the algebraic expression -2x^2+17-15x+7xy?
andrew11 [14]
The given expression is
-2x² + 17 - 15x + 7xy

The algebraic expression may be written as
-2x² + 7xy - 15x + 17

The constant term does not contain either x or y.
Therefore  17 is the constant term.

Answer: 17

7 0
3 years ago
Jabes travelled 3406km in 8days. if he travelled the same distance every day, how many kilometers did he travel per day?
lisabon 2012 [21]

Jabes travels 425.75km per day.

Unit rate is the amount of a certain item related to a single unit of another item.

In the question, we are given that Jabes traveled 3406km in 8 days

We have to find the distances that Jabes travel per day which will be the unit rate of distance per day.

The total distance that jabes traveled in 8 days = 3406 km

Thus, the distance per day jabes traveled can be calculated as:

8 days ⇒3406 km

or, 1 day⇒ 3406/8days = 425.75km

Thus,jabes traveled 425.75 km per day, using the unit rate.

Learn more about the unit rate here:

brainly.com/question/4895463

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8 0
2 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
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