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Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!
Answer:
Options (1), (3) and (5)
Step-by-step explanation:
By the property of midsegment,
Segment joining midpoints of two sides of a triangle measures the half of the third side of the triangle and midsegment is parallel to the third side.
Since, points U, V and W are the midpoints of the sides JK, KL and LJ,
UW =
UV =
VW =
UV ║ JL
UW ║ KL
VW ║JK
Therefore, options (1), (3) and (5) are true.