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Mars2501 [29]
3 years ago
9

Help with how to do this angle problem

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0

Answer:

75

Step-by-step explanation:

180-105=75

shutvik [7]3 years ago
6 0

Answer:

122

Step-by-step explanation:

Angles of a quadrilateral add up to 360 then let the angle with x be y

So

119+78+105+y=360

302+y=360

y=360-302

y=58

Now

x+y=180 (angles on a straight line)

x+58=180

x=180-58

x=122

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aliina [53]
x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0


4 0
3 years ago
its 76 degrees fahrenheit at the 6000-foot level of a mountain, and 49 degrees Fahrenheit at the 12000-foot level of the mountai
brilliants [131]

T = \frac{-9}{2}x + 103 is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.

<em><u>Solution:</u></em>

The linear equation in slope intercept form is given as:

T = cx + k ------ (i)

Where "t" is the temperature at an elevation x

And x is in thousands of feet

<em><u>Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain</u></em>

Given, when c = 6 thousand ft and T = 76^{\circ} fahrenheit

This implies,

From (i)

76 = c(6) + k

76 = 6c + k

⇒ k = 76 - 6c  ----- (ii)

<em><u>Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain</u></em>

Given, when c = 12 thousand ft and T = 49^{\circ} fahrenheit

This implies,

From (i)

49 = c(12) + k

49 = 12c + k

Substitute (ii) in above equation

49 = 12c + (76 - 6c)

49 = 12c + 76 - 6c

49 - 76 = 6c

6c = -27

c = \frac{-9}{2}

Substituting the value of c in (ii) we get

k = 76 - 6( \frac{-9}{2})\\\\k = 76 + 27 = 103

Substituting the value of c and k in (i)

T = \frac{-9}{2}x + 103

Where "x" is in thousands of feet

Thus the required linear equation is found

5 0
3 years ago
-⅕ (10-5+25x)<br> Please help!
Yanka [14]

Answer:

--\frac{1}{5} * (5+25x)\\-\frac{1}{5} *5-\frac{1}{5}(25x)\\-1-\frac{1}{5}(25x)\\-1 -1 (5x)\\01-5x

Step-by-step explanation:

7 0
3 years ago
To find solutions of equations should we look for x-intercepts or y-intercepts in a graph
Vladimir [108]
No one is going to be a great way to start a
3 0
2 years ago
Read 2 more answers
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kupik [55]

Answer:

The graph of a linear equation forms a straight line, whereas the graph for a non-linear relationship is curved. ... A non-linear relationship reflects that each unit change in the x variable will not always bring about the same change in the y variable

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