Answer:
(2pi)/5
Step-by-step explanation:
The cosine function cos(x) has a period of 2*pi.
If we change the argument of the cosine, the new argument will have a period of 2*pi. If the new argument is 5x, we have that the period will be:
5x = 2*pi
x = 2*pi/5
The period of this function will be (2pi)/5, because for every (2pi)/5 change in the value of x, the function will have the same value. The value of 5 multiplying the cosine does not interfere in the period.
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
The answer to the equation is 8
Trial and error
tried 8 x 6 =48
i used 10 x 5 to get closer to 100
10 x 5= 50
50+ 48= 98 all I need is 6 which is 2 x 3
8 x 6 = 48
5 x 10= 50
3 x 2 = 6
Total = 104
Hope this helps
Answer:
Length, l = 11 ft.
Width, w = 9 ft.
Step-by-step explanation:
From the given data, the area of the rectangle = 99 ft².
Area of the rectangle = Length, l X Width, w
Here, Length, l = 7 more than twice the width
⇒ Length, l = 7 + 2w
Therefore, Area, A = 99 = (7 + 2w)w
⇒ 99 = 7w + 2w²
⇒ 2w² + 7w - 99 = 0
Solve the Quadratic equation using the formula: x =
for the quadratic equation ax² + bx + c = 0.
Therefore, w = 


Since,
we get:

This gives two values of 'w', viz., w =
, 

⇒ w =
, -9.
We take the integer values.
If w = -9, then l = 2(-9) + 7
⇒ l = - 18 + 7 = - 11
Therefore, the length, l of the rectangle = - 11 ft.
and the width, w of the rectangle = - 9 ft.
Hence, the answer.