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oksano4ka [1.4K]
3 years ago
11

12/7 = k/8 Solve for k

Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

13 5/7

Step-by-step explanation:

Rewrite the equation as  

k

8

=

12

7

.

k

8

=

12

7

Multiply both sides of the equation by  

8

.

8

⋅

k

8

=

8

⋅

12

7

Simplify both sides of the equation.

Tap for more steps...

k

=

96

7

The result can be shown in multiple forms.

Exact Form:

k

=

96

7

Decimal Form:

k

=

13.71428571

…

Mixed Number Form:

k

=

13

5

7

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Here is a triangular pyramid and its net.
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Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

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d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

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Answer:

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Step-by-step explanation:

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