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aalyn [17]
3 years ago
11

In garden peas, tallness (T) is dominant to shortness (t) and axial flowers (A) are dominant to terminal flowers (a). What are t

he expected genotypes and phenotypes of the offspring if a heterozygous tall, heterozygous axillary plant is crossed with a heterozygous tall, terminal plant?
Biology
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

The correct answer is explained below:

Explanation:

  • According to the question, heterozygous tall, heterozygous axillary plant has the following genotype, TtAa.
  • It produces the following gametes: TA, Ta, tA, ta.
  • The heterozygous tall, terminal plant has the following genotype: Ttaa
  • It produces the following gametes: Ta, ta.
  • Crossing them,

           TA                       Ta                     tA                        ta

Ta      TTAa                   TTaa                 TtAa                   Ttaa

     (Tall, Axillary)    (Tall, Terminal)    (Tall, Axillary)    (Tall, Terminal)

ta       TtAa                    Ttaa                  ttAa                   ttaa

     (Tall, Axillary)     (Tall, Terminal)   (Short, Axillary)  (Short, Terminal)

  • The genotypes of the offspring obtained are: TTAa, TTaa, TtAa, Ttaa, ttAa and ttaa respectively.
  • The phenotypes obtained are:
  1. Tall, Axillary = 3.
  2. Tall, Terminal = 3.
  3. Short, Axillary = 1.
  4. Short, Terminal = 1.
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Example of Punnett square: 
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_______IA ____ i 

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Sorry, that was difficult on here, hope it's understandable. 
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case. 

Hope that helps!</span>
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