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11Alexandr11 [23.1K]
3 years ago
10

Which algebraic expression is a polynomial with a degree of 5?

Mathematics
2 answers:
timama [110]3 years ago
8 0

Answer:

2xy4 + 4x2y3 – 6x3y2 – 7x4

Step-by-step explanation:

The degree of a polynomial is the highest exponent of the expression. If there is more than one variable, the degree is calculated by adding the the exponents of the variables in the term.

3x5 + 8x4y2 – 9x3y3 – 6y5  has the term x3y3 and x4y2 which is degree 6

2xy4 + 4x2y3 – 6x3y2 – 7x4  has the term x2y3 and x3y2 which is degree 5

8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4  has the term y6 which is degree 6

–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5 has the term xy5 which is degree 6

nevsk [136]3 years ago
5 0

Answer:

b is your answer

Step-by-step explanation:

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New heat lamps are reported to have the mean lifespan of 100 hours with a standard deviation of 15 hours. Before replacing their
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Answer:

1

  The  correct option is  C

2

 The  correct option is C

3

The  correct option is A

4

The  correct option is B

Step-by-step explanation:

From the question we are told that

    The  population mean is  \mu =  100

     The  standard deviation is  \sigma  =  15

     The  sample size is  n  =  36

     The  sample mean is  \=  x =  105.1

Generally

    The  null hypothesis is  H_o:  \mu =  100 \  hours

     The  alternative hypothesis is  H_a  :  \mu  \ne  100\ hours

Given that the null hypothesis is  true then the  distribution of sample means  \mu_{\=  x }, from a sample size of 36 is  mathematically represented as

        \mu_{\= x } =  \mu

=>     \mu_{\= x } =  100

According to the Central Limit Theorem the test stated in the question is  approximately normally distributed if the sample size is sufficiently large(n  >  30 ) so given that the sample size is  large  n =  36

Then the test is normally distributed and hence the standard deviation is 15

Generally the standard error of mean is mathematically represented as

     \sigma_{\= x } =  \frac{ \sigma }{\sqrt{n} }

=>  \sigma_{\= x } =  \frac{15}{\sqrt{36} }

=>  \sigma_{\= x } = 2.5

Generally  the approximate probability of observing a sample mean of 105.1 or more is mathematically represented as

        P( \=  X   \ge 105.1 ) =1 -  P(\= X  <  105.1) = 1-  P(\frac{\= X -  \mu }{\sigma_{\= x }}

=>    P( \=  X   \ge 105.1 ) =1 -  P(\= X  <  105.1) = 1-  P(Z

From the z-table (reference calculator dot net )

             P(Z

So

  P( \=  X   \ge 105.1 )= 1 -  P(\= X  <  105.1) = 1-  0.97932

 P( \=  X   \ge 105.1 ) =0.02    

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4 years ago
Please help me, I need to pass this class
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Answer:

watch a video for a hint

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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