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3 years ago

10

the cable installer charges 42.50 per hour plus a 60.00 service charge. Your father's firm hires him to took up his company inte

rnet service

1 answer:

Mama L [17]3 years ago

3 0

The equation would be c=42.5x+60
C is cost
X is number of hours

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How much will it cost if 12 people come to the party?

saveliy_v [14]

Answer:

y=5x+25

y=5(12)+25

y=85

Step-by-step explanation:

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3 years ago

Help please 4, 5, 6.......

Assoli18 [71]

4. Supplementary angles together make a straight line (two right angles). So BOE is supplementary to BOC

Answer: ∠BOE

5. Distance and midpoint between (4,-2), (6,8)

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midpoint

$\left(\dfrac{4 + 6}{2}, \dfrac{-2 + 8}{2} \right) = (5, 3)$

Answer: distance 2√26, midpoint (5, 3)

6.That's a rectangle oriented parallel to the axes, width parallel to the x axis of 7 - -3 = 10 and length along y of 1 - - 4 = 5, so an area of 10(5)=50

Answer: 50

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3 years ago

Guys plz help me answer this!!!!

Nutka1998 [239]

Answer:

<u>a= -4</u>

Step-by-step explanation:

subtract 4a from both sides

add 15 to both sides

divide both sides by -3

(order of operations)

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2 years ago

Read 2 more answers

uppose a large telephone manufacturer has a problem with excessive customer complaints and consequent returns of the phones for

vodka [1.7K]

Answer:

The answer is "294.2075".

Step-by-step explanation:

Given:

$\hat{p} = 0.5 \\\\1 - \hat{p} = 1 - 0.5 = 0.5\\\\E = 4\% = 0.04\\\\$

At $83\%$ confidence level the z is ,

$\alpha = 1 - 83\% = 1 - 0.83 = 0.17\\\\\frac{\alpha}{2} = \frac{0.17}{2} = 0.085\\\\Z_{\frac{\alpha}{2}} = Z_{0.085} = 1.3722\\\\n = (\frac{Z_{\frac{\alpha}{2}}}{E})^2 \times \hat{p} \times (1 - \hat{p})\\\\$

$= (\frac{1.3722}{0.04})^2 \times 0.5 \times 0.5\\\\= (34.305)^2 \times 0.5 \times 0.5\\\\= 1,176.83 \times 0.5 \times 0.5\\\\= 1,176.83 \times 0.25\\\\=294.2075$

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3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

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2 years ago