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3 years ago

AB is parallel to CD. AC and BD are perpendicular

Mathematics

1 answer:

Bogdan [553]3 years ago

8 0

Answer:

AB = CD

Step-by-step explanation:

According to the question, data provided is as follows

AB parallel to CD

AC and BD both are perpendicular to AB and CD

Based on the above information, the relationship between AC and BD is

As we know that

Since AC and BD both are perpendicular to AB and CD and these two are parallel. That means they have the same direction as they are parallel

Moreover, in the case of parallel lines, the perpendicular distance between these two lines would remain the same

Therefore

AB = CD

You might be interested in

A school district transported a total of 409 students and teachers to a zoo in buses and vans.

valina [46]

Answer: There are 385 students and teachers who rode to the zoo in buses and 24 students and teachers who rode to the zoo in trains.

Step-by-step explanation:

Since we have given that

Total number of students and teachers = 409

Let the number of vans be x

Let the number of buses be x+5

Number of students and teachers each bus transported = 55

Number of students and teachers each van transported = 12

According to question,

$55(x+5)+12x=409\\\\55x+275+12x=409\\\\67x=409-275\\\\67x=134\\\\x=\frac{134}{67}\\\\x=2$

Total number of students and teachers who rode to the zoo in buses will be

$55(x+5)\\\\=55(2+5)\\\\=55\times 7\\\\=385$

Total number of students and teachers who rode to the zoo in vans will be

$12x\\\\=12\times 2=24$

Hence, there are 385 students and teachers who rode to the zoo in buses and 24 students and teachers who rode to the zoo in trains.

6 0

3 years ago

Help pleaseeeeeeeeee

sergij07 [2.7K]

9514 1404 393

Answer:

47 -6√10

Step-by-step explanation:

As you know, the area of a square is the square of the side length. It can be helpful here to make use of the form for the square of a binomial.

(a -b)² = a² - 2ab + b²

(√2 -3√5)² = (√2)² - 2(√2)(3√5) + (3√5)²

= 2 - 6√10 + 3²(5)

= 47 -6√10

<em>Check</em>

√2-3√5 ≈ -5.29399 . . . . . . . . note that a negative value for side length makes no sense, so this isn't about geometry, it's about binomials and radicals

(√2-3√5)² ≈ 28.02633

47 -6√10 ≈ 28.02633

5 0

3 years ago

Pls help, I don’t understand how to do this

MAVERICK [17]

Answer:

5 parts are shaded and 4 parts are white so:

There are 9 parts all together.

We can then form ratio's of the white areas and the shaded areas:

White Area Ratio =

$\frac{4}{9}$

Shaded Area Ratio =

$\frac{5}{9}$

Let the area of sqaure be equated to x, which means let the entire area of the square equal to x:

x = Area of whole square

Now we can form an equation :

$\frac{5}{9} x = 165$

So now we just need to solve for x:

$x = \frac{165}{ \frac{5}{9} }$

$x = 297$

The area of the square is:

$297 {cm}^{2}$

4 0

3 years ago

Read 2 more answers

Solving equations <br><br> -2(x + 3)=3(2x-10)

nika2105 [10]

Answer:

x=3

Step-by-step explanation:

3 0

3 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

3 years ago