The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
<h3>How to determine the coordinates of the vertex that A maps to after the two reflections?</h3>
From the given figure, the coordinate of the vertex A is represented as:
A = (-5, 2)
<u>The coordinates of the vertex that A maps to after Daniel's reflections</u>
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A' = (5 - 2, 2)
Evaluate the difference
A' = (3, 2)
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A'' = (3, -2 + 4)
Evaluate the difference
A'' = (3, 4)
Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)
<u>The coordinates of the vertex that A maps to after Zachary's reflections</u>
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A' = (-5, -2 + 4)
Evaluate the difference
A' = (-5, 2)
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A'' = (5 - 2, 2)
Evaluate the difference
A'' = (3, 2)
Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
Read more about reflection at:
brainly.com/question/4289712
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For the answer to the question above, the easiest way to determine is changing every runner's speed into the same unit.
<span>First = 10 m/s </span>
<span>Second = 10 miles/min = 16090.34 / 60 m/s (As 1 mile = 1609.34 meter and 1 min = 60 sec) </span>
<span>Second = 260.82 m/s </span>
<span>Third = 10 cm/hr = 10*(0.01)/60*60 (As 1 cm = 0.01 m and 1 hr = 60*60 sec) </span>
<span>Third = 0.000028 m/s </span>
<span>Fourth = 10 km/sec = 10*1000 m/s (As 1 km = 1000 m and time is already in sec) </span>
<span>Fourth = 10000 m/s </span>
<span>So fastest would be the one who covers the largest distance in 1 sec. It would be the fourth one.</span>
Answer:
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Step-by-step explanation:
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Answer: 28
Step-by-step explanation: 6 faces, 12 edges, 8 vertices
Answer:
Solution,
Radius(r)=6 cm
Height(h)=20 cm
Volume of cylinder= pi (r)^2 h
=3.14*(6)^2*20
=3.14*36*20
=2260.8 cm^3
Hope it helps
Good luck on your assignment