Given:
The radius of the sphere is 6 in.
To find:
The volume of the sphere.
Solution:
We know that, the volume of a sphere is
Where, r is the radius of the sphere.
Putting r=6, we get
The volume of the sphere is 904.78 inches cubed.
Therefore, the correct option is C.
Answer:
50 combos
Step-by-step explanation:
Put it into an equation first in order to find x.
2x + 250 = 7x
Subtract 2x from both sides.
250 = 5x
Then divide both sides by 5.
x = 50
Therefore you need 50 combo meals in order to make the amount made equal to the amount paid.
<u>You can check your work by plugging in the number to both.</u>
$250 plus the $2 times 50 combo meals.
250 + 2(50) = 350
$7 times 50 combo meals
7 x 300 = 350
I think 1 / 7 x 7 is the correct answer
Answer:
120.105 square feet.
Step-by-step explanation:
Given that the radius of a cylindrical construction pipe is 1.5 ft, to determine its volume, given that the pipe is 17 ft long, the following calculation must be performed, knowing that the volume of a cylinder arises from multiplying the number pi by the radius at square of the cylinder, and that result by the height of it:
(3.14 x (1.5^2)) x 17 = X
(3.14 x 2.25) x 17 = X
7.065 x 17 = X
120.105 = X
Thus, the volume of the cylinder is 120.105 square feet.
1)
The domain
is every value of x for which f(x) is a real number.
f(x) = 13 / (10-x)
The only x value that would not produce a real number for f(x) is 10, since you
cannot divide a number by zero. Answer is C
2)
F(x)
=(x-6)(x+6)/(x2 - 9)
The vertical asymptotes are x=3 and x=-3. Graph the function on a graphing
calculator to observe the behavior of the function at these points. There is
both a positive and negative vertical asymptote a both x=3 and x=-3. Keep in
mind that the denominator approaches zero at these points, and thus f(x) approaches
either positive or negative infinite, depending on whether the denominator, however small, is a positive or
negative number. Answer is B) 3, -3
3)
F(x) = (x2
+ 4x-7) / (x-7)
Although there is a vertical asymptote as x=7, there is no horizontal asymptote.
This makes sense. As X gets bigger, there is nothing to hold y back from
getting greater and greater. X2 is the dominant term, and it’s only
in the numerator. A) none
4)
(x2 +
8x -2) / (x-2)
This function is very similar in structure to the previous one. Same rules
apply. Dominant term only in the numerator means no horizontal asymptote.
A)None
5)
Our
function approaches 0 as x approaches infinite, and has a vertical asymptote at
x=2 and x=1.
Here’s an easy example: 10 / ((x-2)*(x-1)). At x=2 and x=1, there is both a
positive and negative vertical asymptote. As x approaches infinite, the
numerator is dominated by the denominator, which contains x (actually x2 ),
and thus y approaches zero.
