Answer:
5 mph
Step-by-sep explanation:
To find of out the difference between the speed of the two drivers in miles per hour (not in miles per minute), first, calculate the unit rate or speed of driver 1 using the graph, and driver 2 using the table given.
Unit rate/speed = distance travelled/time = y/x.
Speed of Driver 1/unit rate:
The graph shows 1.5 miles (y) is travelled in 2 minutes (x).
Convert the 2 minutes to hour, you will have:
![\frac{2}{60} = \frac{1}{30} hr](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B60%7D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20hr%20)
Speed in mph = ![\frac{y}{x} = \frac{1.5}{\frac{1}{30}} = 1.5*\frac{30}{1} = 45](https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7Bx%7D%20%3D%20%5Cfrac%7B1.5%7D%7B%5Cfrac%7B1%7D%7B30%7D%7D%20%3D%201.5%2A%5Cfrac%7B30%7D%7B1%7D%20%3D%2045%20)
Speed of Driver 1 in mph = 45 mph
Speed of Driver 2/unit rate:
The table shows 2.5 miles (y) is travelled in 3 minutes (x).
Convert the 3 minutes to hour, you will have:
![\frac{3}{60} = \frac{1}{20} hr](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B60%7D%20%3D%20%5Cfrac%7B1%7D%7B20%7D%20hr%20)
Speed in mph = ![\frac{y}{x} = \frac{2.5}{\frac{1}{20}} = 2.5*\frac{20}{1} = 50](https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7Bx%7D%20%3D%20%5Cfrac%7B2.5%7D%7B%5Cfrac%7B1%7D%7B20%7D%7D%20%3D%202.5%2A%5Cfrac%7B20%7D%7B1%7D%20%3D%2050%20)
Speed of Driver 2 in mph = 50 mph
Difference between the speed of the two drivers = 50 - 45 = 5 mph
Answer:
B. The statement is false because -5 is to the left of -3 on a number line.
Step-by-step explanation:
Statement: -5 > -3
A number line system is a method of locating and expressing the position of directed numbers. It has its middle mark as zero, so that all numbers to the left of zero are less than zero and all numbers to the right of zero are greater than zero.
Comparing two directed numbers -5 and -3. It can be observed that -3 is greater than -5, so that -5 is to the left of -3 on a number line.
Thus -5 > -3 is false.
I think it is C: 4.95m + 0.72f although this isn't in my curriculum I think its correct.