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artcher [175]
2 years ago
13

A farmer has 4,700 carrots to put in bunches of 15 carrots. He plans to sell the carrots for $5 per bunch. How much money will t

he farmer make if he sells all the bunches of carrots?
Mathematics
2 answers:
kumpel [21]2 years ago
7 0
4700 divided by 15 = 313.333
the farmer has 313 bunches of carrots

313 x $5 = $1565

if the farmer sells all the bunches, he will make $1,565
baherus [9]2 years ago
6 0

Answer:

farmer make 313 bunch of carrot

Step-by-step explanation:

given data

Total Carrots = 4700

Number of  bunch = 15

sell carrots = $5 per bunch

to find out

how many bunches will the farmer make

solution

first we get here no of bunch that is express as

number of bunch = Total Carrots ÷ Number of  bunch   .......................1

put here value we will get number of bunch

number of bunch =

number of bunch = 313.3

so that here farmer make 313 bunch of carrot

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A function is a relation in which each element of the domain, or x-value, is mapped to one element of the range, or y-value.

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3 years ago
PLEASE HELP
katrin2010 [14]

The game that is  used for the scenario above in terms of fair play is  using a balloon. Here, the player will hit the balloon.

<h3>What is the scenario under the balloon game?</h3>

The rule of play are:

This is a classic game with simple rules which are:

  • Each player to hit the balloon up and it bonce into the air but when one should not allow it to touch the ground.,
  • Players would be tied together in twos and they will juggle a lot of balloon and it have to be more than 1 balloon with one of their hands tied to their back.

A scenario of the worksheet game whose expected value is 0 is given below:

Assume that it costs about $1 for a player to play the billon game and as such, if  the player hits a balloon, they will be given $3. what can you say. Can you say that it this game is fair or not? and who has the biggest advantage.

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(4)(0.313) + (-1)(0.313)

= 0.939 approximately

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Learn more about fair play from

brainly.com/question/24855677

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Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

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