All categories

3 years ago

What is x divided by 3 plus 2 divided by 5 equals one over fifteen

Mathematics

1 answer:

dolphi86 [110]3 years ago

6 0

x/3 + 2/5 = 1/15

x/3 = 1/15 - 2/5

x/3 = 1/15 - 6/15

x/3 = -5/15

x = (-1/3) * 3

x = -1

Answer: x = -1

You might be interested in

Simplify the expression: 7y+9+7–2y

larisa [96]

Answer:

5y+16

Step-by-step explanation:

see image below:)

6 0

2 years ago

Read 2 more answers

Determine the values of k and p so that the solution is "All Reals" when solving for y:

Angelina_Jolie [31]

Answer:

The value of k is $\pm 9$ and The value of p is - 23

Step-by-step explanation:

Given equation as :

81 y - 17 = k² y + 6 + p

The equation has real solution ,

Now for real solution the equation have no solution

∵ The equation has no solution the ,

The coefficient of y must be equal

I.e 81 = k²

Or, k = $\sqrt{81}$

∴ k = $\pm 9$

Again , If the coefficient of y is same then the equation is written as

6 + p = - 17

or, p = - 17 - 6

or, p = - 23

Hence The value of k is $\pm 9$ and The value of p is - 23 Answer

6 0

2 years ago

The equation of a line is (3)/(5)x+(1)/(3)y=(1)/(15) . The x-intercept of the line is , and its y-intercept is .

boyakko [2]

bxf-mgii-whr

Step-by-step explanation:

come I will teach

6 0

3 years ago

Which of the following methods can be used to find the derivative of y = arcsin x with respect to z ?

vfiekz [6]

Answer:

B) Ill only

Step-by-step explanation:

This is because y = arcsin x can be re-written as sin y = x, We then differentiate sin y = x implicitly with respect to z to obtain

d(siny)/dz = dx/dz

(cosy)dy/dz = dx/dz

dy/dz = (1/cosy)dx/dz

5 0

2 years ago

Draw at least six different sized rectangles that have an area of 64 square units

olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

$A=x*y$

$A=64\ units^{2}$

$x*y=64$ --------> equation 1

let's assume different values of x to get the different values of y

case 1) For x=64 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/64$

$y=1\ units$

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

case 2) For x=32 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/32$

$y=2\ units$

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

case 3) For x=16 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/16$

$y=4\ units$

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

case 4) For x=30 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/30$

$y=\frac{32}{15} =2\frac{2}{15} \ units$

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

case 5) For x=40 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/40$

$y=1.60\ units$

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

case 6) For x=60 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/60$

$y=\frac{16}{15} =1\frac{1}{15} \ units$

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

3 0

2 years ago