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andrew-mc [135]
3 years ago
11

SOMEBODY HELP PLS, WILL GIVE BRAINLIEST TO RIGHT ANSWER

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

a. I, III, II

Step-by-step explanation:

To answer this question, lets take a look at I, II, and III.

First, lets take a look at I. It states that the m∠SQT = 180 by the definition of a straight angle. We can get that the m∠SQT = 180 just by looking at the image and by knowing our second given. So I just has to be below the second given.

Now, lets take a look at II. It states that m∠SQV + m∠VQT = 180 by the Substitution Property of Equality. We can find that m∠SQV + m∠VQT = 180 just by looking at the image along. But knowing that it is found by the Substitution Property of Equality, we can find that m∠SQV + m∠VQT = 180 was derived from the fact that m∠SQT = 180 and that m∠SQV + m∠VQT = m∠SQT, or I and III. So II was derived from I and III, and II should come after I and III.

Now lets look at III. It states that m∠SQV + m∠VQT = m∠SQT by the Angle Addition Postulate. Since III is found by the Angle Addition Postulate, we can find that III was derived from I, and III should come after I.

So knowing that II should come after III and I, and that III should come after I, we can find that the order should be I, III, II.

I hope you find my answer and explanation to be helpful. Happy studying.

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DerKrebs [107]

Answer: At point (-\frac{1}{2},-\frac{1}{2})

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In other words, the diagonals of a square meet at their midpoint, which is found as the following:

(x,y) = (\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})

The opposite vertices of the given square are (-2,6) and (1,-7).

So, the intersection is

(x,y) = (\frac{-2+1}{2} ,\frac{6-7}{2})

(x,y) = (-\frac{1}{2},-\frac{1}{2} )

The diagonals of square with vertices (-2,6)(6,1)(1,-7)(-7,-2) intersect at point (-\frac{1}{2},-\frac{1}{2} ).

4 0
3 years ago
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kari74 [83]

Could you give Brainliest please???

Answer:

y = 2 - 1/2x

Step-by-step explanation:

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To find y you must isolate it first.

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(Subtract 3x to isolate the y term)

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y = 2 - 3/6x

(Simplify)

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77julia77 [94]

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grin007 [14]

Given:

In the circle P, ABCD is inscribed quadrilateral.

And, ∠DAB = 110°, ∠ABC = 72°

To find the value of ∠ADC.

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According to the theorem,

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The value of ∠ADC is 108°.

Hence, Option b is the correct answer.

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