Question

Consider the allelic frequency of the alleles of the bigmouth gene in a population of 10 people. In this population, 2 have the genotype B8, 3 have the genotype bb, and the rest are heterozygotes. What is the frequency q of the recessive allele b?
A. q 0.55
B. q 0.50
C. q 0.45
D. q 0.2
E. The allele frequencies can only be determined if the population is in Hardy-Weinberg equilibrium

Answer 1

Answer:

A. q 0.55

Explanation:

Frequency of genotye "BB" $= \frac{2}{10}$$=0.2$

Frequency of genotye "bb" $= \frac{3}{10}$$=0.3$

Frequency of genotye "Bb" $= \frac{10-(2+3)}{10}$$=0.5$

Frequency of bb is represented as "$q^{2}$" as per  Hardy Weinberg's principle.

Thus, frequency q of the recessive allele b is represented by

$q= \sqrt{q^{2} } \\q = \sqrt{0.3} \\q = 0.547\\q=0.55$

Hence, option A is correct.