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3 years ago

Math...question.. Help please..DUE tomarrow..... BEST....answer all points!!,!,

Mathematics

1 answer:

Georgia [21]3 years ago

4 0

Answer:

Step-by-step explanation:

put the coordinates in the right place

connect the dots and use the shape and the coordinates to help you decide or prove that the shape is an isosceles triangle

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EEF has vertices D(1, 3), E(2, -4), and F(-3, 1). What are the vertices T<4, 1> (DEF).

Triss [41]

The vertices T<4, 1> (DEF) are D' = (5, 4), E' = (6, -3) and F' = (1, 2)

<h3>How to determine the vertices?</h3>

The vertices of the triangle are given as:

D(1, 3), E(2, -4), and F(-3, 1).

The transformation represented by T<4, 1> (DEF) is:

(x,y) = (x + 4, y + 1)

So, we have;

D' = (1 + 4, 3 + 1)

D' = (5, 4)

E' = (2 + 4, -4 + 1)

E' = (6, -3)

F' = (-3 + 4, 1 + 1)

F' = (1, 2)

Hence, the vertices T<4, 1> (DEF) are D' = (5, 4), E' = (6, -3) and F' = (1, 2)

Read more about transformation at:

brainly.com/question/1548871

#SPJ1

8 0

2 years ago

the rational roots of a polynomial function f(x) can be written in the form p/q where p is a factor of the leading corfficient o

Lorico [155]

False.

The Rational Root theorem states that P is a factor of the constant term and q is a factor of the leading coefficient.

4 0

3 years ago

What is the answer to this question?

geniusboy [140]

Answer:

A-75 and B-25

Step-by-step explanation:

Firstly, divide the 200 students by the amount of sections (8) and that gives you 25 a section. Since year 7 has 3 sections and year 9 has 1, 3(25)=75 and 25(1)=25.

8 0

3 years ago

Read 2 more answers

(−7c+8d)0.6<br><br> khan academy pls help.

Burka [1]

Answer:

$\sf -4.2c+4.8d$

Step-by-step explanation:

$\sf \left(-7c+8d\right)\cdot \:0.6$

$\sf 0.6\left(-7c+8d\right)$

Apply distributive property

$\sf 0.6\left(-7c\right)+0.6\times \:8d$

$\sf -4.2c+4.8d$

Have a good day!

4 0

3 years ago

Acircular ring has across -section as shown .If the outer radias 20 mm and the inner radius 16 mm .Calculate the cross - section

Zina [86]

Answer:

452.45mmm^2

Step-by-step explanation:

Step one:

Given data

outer radius R= 20mm

inner radius r= 16mm

let us find the area of the outer circle

Area= πR^2

Area= 3.142*20^2

Area= 3.142*400

Area= 1256.8 mm^2

let us find the area of the inner circle

Area= πr^2

Area= 3.142*16^2

Area= 3.142*256

Area= 804.35 mm^2

Hence the area of the section is

Area of outer- Area of inner

=1256.8-804.35

=452.45mmm^2

4 0

3 years ago