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3 years ago

What is the value of x in 2(5^x) = 14?

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

4 0

Answer:

0.34

Step-by-step explanation:

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Gemma and Leah are both jewelry makers. They made 39 necklaces. Each necklace has exactly 104 beads on it. How many beads did th

Kay [80]

Answer:

4056

Step-by-step explanation:

39 necklaces

104 beads/necklace

number of beads = number of necklaces * number of beads per necklace

number of beads = 39 * 104 = 4056

8 0

3 years ago

Tell what whole number you can substitute for xx in the following list so the numbers are ordered from least to greatest. 1/x,x/

olasank [31]

X/3 has to be smaller tha 80%
so x can be 2 since 2/3=66% about
1/2 is less thn 2/3

answer is x is 2

4 0

3 years ago

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Solve 8 = 2^x + 4 x = −4 x = −1 x = 0 x = 7

TEA [102]

None of these answers match up to the equation. The answer is 2. 2^2, 2x2=4
4+4=8
8=2^2+4

8 0

3 years ago

Solve for x : log(3x) + log(x + 4) = log(15). Please explain it to me.

zlopas [31]

Answer:

x = 1

Explanation:

$\sf \rightarrow log(3x) + log(x + 4) = log(15)$

Rule: log(a) + log(b) = log(ab)

$\sf \rightarrow log(3x(x + 4)) = log(15)$

cancel out log on both sides

$\sf \rightarrow 3x(x + 4) = 15$

relocate constant variable

$\sf \rightarrow 3x^2 + 12x -15 = 0$

take 3 as a common factor

$\sf \rightarrow 3(x^2 + 4x -5) = 0$

divide both sides by 3

$\sf \rightarrow x^2 + 4x -5 = 0$

middle term split

$\sf \rightarrow x^2 + 5x -x-5 = 0$

factor common terms

$\sf \rightarrow x(x + 5) -1(x+5)= 0$

collect into groups

$\sf \rightarrow (x-1)(x+5)= 0$

set to zero

$\sf \rightarrow x-1 = 0 , \ x+5= 0$

relocate variables

$\sf \rightarrow x = 1, \ x = -5$

There must be a positive solution for log, so the solution is only x = 1

3 0

2 years ago

Read 2 more answers

There are 5 4/11 pounds of green apples. There are 3 2/3 times as many red apples. How many pounds of red apples are there?

enyata [817]

Answer:

19 2/3

Step-by-step explanation:

5 4/11 * 3 2/3 = 19 2/3.

5 0

3 years ago

Read 2 more answers