Answer:
x = -5
Step-by-step explanation:
Simplifying
6x + -3(x + -8) = 9
Reorder the terms:
6x + -3(-8 + x) = 9
6x + (-8 * -3 + x * -3) = 9
6x + (24 + -3x) = 9
Reorder the terms:
24 + 6x + -3x = 9
Combine like terms: 6x + -3x = 3x
24 + 3x = 9
Solving
24 + 3x = 9
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-24' to each side of the equation.
24 + -24 + 3x = 9 + -24
Combine like terms: 24 + -24 = 0
0 + 3x = 9 + -24
3x = 9 + -24
Combine like terms: 9 + -24 = -15
3x = -15
Divide each side by '3'.
x = -5
Hope this Helps
I hope this is correct
Answer:
8 days
Step-by-step explanation:
4/5= 8/10
Answer:
circle
Step-by-step explanation:
circle is a set of all those points in a plane that lie the same distance from a single point in the plane .
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN