The "horizontal" distance is 8-2 = 6.
The "vertical" distance is 7-3 = 4.
The Pythagorean theorem tells you the straight line distance is then
√(6² + 4²) = √52 = 2√13 ≈ 7.21
Answer:
- plane: 550 mph
- wind: 50 mph
Step-by-step explanation:
If p and w represent the speeds of the plane and wind, respectively, the speed into the wind is ...
p - w = (3000 mi)/(6 h) = 500 mi/h
And, the speed with the wind is ...
p + w = (3000 mi)/(5 h) = 600 mi/h
Adding these two equations gives us ...
2p = 1100 mi/h
p = 550 mi/h . . . . . . . divide by 2
Then the wind speed is ...
w = 600 mi/h - p = (600 -550) mi/h
w = 50 mi/h
The rate of the plane in still air is 550 mi/h; the rate of the wind is 50 mi/h.
Answer:
The proof is given below.
Step-by-step explanation:
Given m∠AEB = 45° and ∠AEC is a right angle. we have to prove that EB divides ∠AEC into two congruent angles, it is the angle bisector.
Given ∠AEC=90° (Given)
∠AEC=∠AEB+∠BEC
⇒ 90° = 45° +∠BEC (Substitution Property)
By subtraction property of equality
⇒ ∠BEC = 90° - 45° = 45°
Hence, both angles becomes equal gives ∠AEB≅∠BEC
Since EB divides ∠AEC into two congruent angles, ∴ EB is the angle bisector.
Answer:
The area of the rectangle is 20 square units
Step-by-step explanation:
Through the x values of the ordered pairs, we can see that the length of the rectangle is 5

Through the y-values of the ordered pairs, we can see that the width of the rectangle is 4

The area can be found by multiplying the length and width, so this means

Recall your d = rt, distance = rate * time
so, keeping in mind that both trains are going at the same speed, say speed of "r" mph, after 212 hours A arrived at station A and after 4 hours, B arrived at station B.
now, the distance covered by train A is say "d", we know both stations are 585 miles apart, so, if train A covered "d" miles in those 212 hours, then train B covered the slack from 585 and d, that is "585 - d".