Answer:
Step-by-step explanation:
given are the two following linear equations:
f(x) = y = 1 + .5x
f(x) = y = 11 - 2x
Graph the first equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis.
If x = 0, then f(0) = 1 + .5(0) = 1
If y = 0, then f(x) = 0 = 1 + .5x
-.5x = 1
x = -2
The resulting data points are (0,1) and (-2,0)
Graph the second equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis.
If x = 0, then f(0) = 11 - 2(0) = 11
If y = 0, then f(x) = 0 = 11 - 2x
2x = 11
x = 5.5
The resulting data points are (0,11) and (5.5,0)
At the point of intersection of the two equations x and y have the same values. From the graph these values can be read as x = 4 and y = 3.
Answer:
when P(x,y) is reflected in y=x line then
P(x,y) = P(y,x)
A(2, -1)= A(-1, 2)
B(-2, -1) = B(-1, -2)
C(2, 1)= C(1, 2)
D(1,2)= D(2,1)
Step-by-step explanation:
I believe your answer is D, scatterplot. hope this helps
There is a special kind of substitution which some books call it by comparison.
When the two equations are both
y=some function of x
y=some other function of x, then
we can substitute the second equation into the first giving
some function of x = some other function of x and start solving.
For example,
<span>y = –2x + 8
y = x – 1
substitute second into first
x-1=-2x+8
isolate x on left,
3x=9
x=3
second step is to substitute x=3 into second equation to get
y=x-1=3-1=2
Therefore the solution is (3,2)</span>
