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3 years ago

Two trains leave stations

1 answer:

6 0

Total distance 272 miles.
Total speed (when travelling toward each other) = 75+95=170 mph
Time to meet = 272/170=1.6 hours

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1.) 2.) -PLEASE ANSWER-

Misha Larkins [42]

Answer:

9/10

30%

Step-by-step explanation:

Only in trial number 4, there is just one correct answer. In all other 9 trials at least 2 answers were correct. So the probability is 9 out of 10 trials give a winning outcome, in short, 9/10.

Giving birth to three males first, is true in 3 out of 10 trials. You can count the total numbers of Y's in the last column.

So 3/10 which is 0.3 which is the same as 30%.

6 0

4 years ago

-0.6w=2.4 Please answer Hggjigj

SashulF [63]

Final Answer: $w = -4$

Steps/Reasons/Explanation:

Question: Solve $-0.6w = 2.4$ .

Step 1: Divide both sides by $-0.6$ .

$w = -\frac{2.4}{0.6}$

Step 2: Simplify $\frac{2.4}{0.6}$ to $4$ .

$w = -4$

~I hope I helped you :)~

8 0

3 years ago

Read 2 more answers

in a box full of oranges, apples, and pears in a ratio 2:5:6. What is the total weight of the fruits in the box if it was known

spin [16.1K]

Answer:

31.2 lbs

Step-by-step explanation:

Let 2x = weight of oranges

5x = weight of apples

6x = weight of pears

2x + 5x + 6x = total weight

2x = 4.8

x = 2.4

4.8 + 5(2.4) + 6(2.4) = 4.8 + 12 + 14.4

= 31.2 lbs

7 0

3 years ago

Which situation relates to the graph?

enyata [817]

D because there are 10 gallons of gas remaining as you can see on the y axis and 10 gallons is being used for each 10 miles because 10 x 10 is 100 and the graph is counting up by 10

8 0

3 years ago

An elementary school is offering 2 language classes: one in Spanish (S) and one in French (F). Given that P(S) = 50%, P(F) = 40%

nikklg [1K]

Answer:

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .

Step-by-step explanation:

We are given that an elementary school is offering 2 language classes ;

Spanish Language is denoted by S and French language is denoted by F.

Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}

P(F) = 0.4 {Probability of students taking French language}

$P(S\bigcup F)$ = 0.7 {Probability of students taking Spanish or French Language}

We know that, $P(A\bigcup B)$ = $P(A) + P(B) -$ $P(A\bigcap B)$

So, $P(S\bigcap F)$ = $P(S) + P(F) - P(S\bigcup F)$ = 0.5 + 0.4 - 0.7 = 0.2

$P(S\bigcap F)$ means Probability of students taking both Spanish and French Language.

Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5

P(F)' = 1 - P(F) = 1 - 0.4 = 0.6

$P(S'\bigcap F')$ = 1 - $P(S\bigcup F)$ = 1 - 0.7 = 0.3

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);

P(S/F) = $\frac{P(S\bigcap F)}{P(F)}$ = $\frac{0.2}{0.4}$ = 0.5

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');

P(F'/S') = $\frac{P(S'\bigcap F')}{P(S')}$ = $\frac{1- P(S\bigcup F)}{1-P(S)}$ = $\frac{0.3}{0.5}$ = 0.6 .

Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears ; This question is incomplete please provide with complete detail.

7 0

4 years ago