Question

For the rule y= 4 - x2, calculate the y-values that complete the table below

Answer 1

Answer:

$\begin{center}\begin{tabular}{ c| c } x & y=4-x^2 \\ -3 & -5 \\ -2 & 0\\-1 & 3 \\ 0 &4 \\ 1&3\\2&0\\3&-5\end{tabular}\end{center}$

Step-by-step explanation:

The given function is $y=4-x^2$

When x=-2 we have $y=4-(-2)^2=4-4=0$

When x=-1 we have $y=4-(-1)^2=4-1=3$

When x=0 we have $y=4-(0)^2=4-0=4$

When x=1 we have $y=4-(1)^2=4-1=3$

When x=2 we have $y=4-(2)^2=4-4=0$

When x=3 we have $y=4-(3)^2=4-9=-5$

The complete table is

$\begin{center}\begin{tabular}{ c| c } x & y=4-x^2 \\ -3 & -5 \\ -2 & 0\\-1 & 3 \\ 0 &4 \\ 1&3\\2&0\\3&-5\end{tabular}\end{center}$