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3 years ago

if f(x) and g(x) are a quadratic function but (f + g)(x) produce the graph below, which statement must be true

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

The leading coefficients are opposites.

For instance
f(x) = 2x^2 + 5x + 6
g(x) = -2x^2 + 8x - 3
here the leading coefficients 2 and -2 are opposites

Adding function f(x) and g(x) gets us
f(x) + g(x) = (2x^2+5x+6) + (-2x^2+8x-3)
f(x) + g(x) = (2x^2-2x^2) + (5x+8x) + (6-3)
f(x) + g(x) = 0x^2 + 13x + 3
f(x) + g(x) = 13x + 3

The two quadratics add up to a linear equation

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Pls helpeddddddddddddddd

Dmitrij [34]

Answer:

Step-by-step explanation:

Remark

The easiest way to do this is to Substitute for y in the top equation.

2x + 4y = 18 Divide by 2

2x/2 + 4y/2 = 18/2

x + 2y = 9

Substitute -3x + 2 in for y in the equation above

x + 2(-3x + 2) = 9

x - 6x + 4 = 9

Combine like terms on the left

-5x + 4 = 9

Subtract 4 from both sides.

-5x + 4-4 = 9- 4

-5x = 5

Divide by -5

-5x/-5 = 5/-5

x = - 1

That makes A and C incorrect.

y = -3x + 2

y = -3(-1) + 2

y = 3 + 2

y = 5

The correct answer should be (-1,5) which is B

7 0

3 years ago

Put 3/4 7/8 3/5 in order from least to greatest

andrew-mc [135]

I am not sure of the correct answer but cross multiply to find which has the bigger number and smallest to put them in order.

4 0

3 years ago

Read 2 more answers

Determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of cent

Iteru [2.4K]

Answer:

It seems the question is incomplete as the two data sets implied from the question are not visible.

However, two data sets having identical measures of center have a difference.

Step-by-step explanation:

Let's consider these two data sets:

2, 2, 3, 5, 6, 6 and 1, 1, 1, 1, 1, 19

Both were contrived.

The most reliable among the measures of center is the mean. The mean of each is calculated by summing the data and dividing by the number of elements. In both sets, the mean is 4.

The data in the first set seem to be concentrated around the mean indeed. But for the second data set, one of them, 19, is obviously very far from the others and the mean. We need another measure to describe this: standard deviation.

Its formula is:

$\rho=\sqrt{\dfrac{\sum (x-\overline{x})^2}{n}}$

$x$ represents each data, $\overline{x}$ is the mean and $n$ is the number of items. $x-\overline{x}$ is the deviation from the mean of each data item.