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Mamont248 [21]
3 years ago
6

if f(x) and g(x) are a quadratic function but (f + g)(x) produce the graph below, which statement must be true

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
The leading coefficients are opposites.

For instance
f(x) = 2x^2 + 5x + 6
g(x) = -2x^2 + 8x - 3
here the leading coefficients 2 and -2 are opposites

Adding function f(x) and g(x) gets us
f(x) + g(x) = (2x^2+5x+6) + (-2x^2+8x-3)
f(x) + g(x) = (2x^2-2x^2) + (5x+8x) + (6-3)
f(x) + g(x) = 0x^2 + 13x + 3
f(x) + g(x) = 13x + 3

The two quadratics add up to a linear equation
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Step-by-step explanation:

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5 0
3 years ago
A farmer sells 8.7 kilograms of pears and apples at the farmer's market. 2 5 of this weight is pears, and the rest is apples. Ho
Ivenika [448]

Answer: 5.22kg

Step-by-step explanation:

From the question, a farmer sells 8.7 kilograms of pears and apples at the market. Of the pears and apples sold, 2/5 of this weight is pears, and the rest is apples. To calculate the kilograms of apple sold goes thus:

Total kilograms sold = 8.7kg

Fraction of pears weight = 2/5

Pears kilograms sold = 2/5 × 8.7

= 0.4 × 8.7

= 3.48kg

Since the kilograms of pears sold is , 3.48kg, to get the kilograms of apple sold, we subtract 3.48kg from 8.7kg. This will be:

= 8.7kg - 3.48kg

= 5.22kg

8 0
3 years ago
You are trying to heat up a cup of water with a butane lighter.
algol13

Answer:

Step-by-step explanation:

Remark

The formula for this is

Heat = m * c * Δt

Givens

Heat = unknown

m = 200 grams

c = 4.184 Joules / grams oC

Δt = the change in temperature = 35.7 - 22.3 = 13.4

Solution

Heat = 200 * 4.184 * 13.4

Heat = 11213 Joules

Heat = 11.2 Kj

It's hard to get the correct number of sig digs because the 200 is not qualified in any way.

Part 2.

This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.

Heat of Combustion = Heat Given Up / Number grams burned.

Heat of Combustion = 11.2 Kj / 0.23 grams

Heat of Combustion = 48.8 Kj / gram

8 0
3 years ago
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