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Mamont248 [21]
3 years ago
6

if f(x) and g(x) are a quadratic function but (f + g)(x) produce the graph below, which statement must be true

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
The leading coefficients are opposites.

For instance
f(x) = 2x^2 + 5x + 6
g(x) = -2x^2 + 8x - 3
here the leading coefficients 2 and -2 are opposites

Adding function f(x) and g(x) gets us
f(x) + g(x) = (2x^2+5x+6) + (-2x^2+8x-3)
f(x) + g(x) = (2x^2-2x^2) + (5x+8x) + (6-3)
f(x) + g(x) = 0x^2 + 13x + 3
f(x) + g(x) = 13x + 3

The two quadratics add up to a linear equation
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jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
What’s in a equation or Leniar function y axis 1 and negative 7 and x axis negative 3 and 1
Elodia [21]

A linear function is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable. For example, a common equation,  

y

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m

x

+

b

, (namely the slope-intercept form, which we will learn more about later) is a linear function because it meets both criteria with  

x

and  

y

as variables and  

m

and  

b

as constants.  It is linear: the exponent of the  

x

term is a one (first power), and it follows the definition of a function: for each input (

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5 0
3 years ago
HELP I will mark branliest!!!!
Klio2033 [76]

Answer:

Rah&fyjftyhh

Step-by-step explanation:

for TY hfhef

7 0
2 years ago
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Explain how to compare two lengths that are measured in different sized units
nalin [4]
There are conversion tables everywhere that assist you in changing a different unit into another. Depending on what it is, you can also compare weight into water, cm into m and backwards.
8 0
3 years ago
Can someone please give me the answers to this? ... please ...
Gelneren [198K]

Step-by-step explanation:

the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).

so,

1.

(9, 7) to (4, -3)

midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)

2.

(-7, -5) to (2, 1)

midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)

3.

now we have the midpoint and need the second point.

(4, 2) over (3, 4) to (x, y)

3 = (4 + x)/2

6 = 4 + x

x = 2

4 = (2 + y)/2

8 = 2 + y

y = 6

4.

(-2, 1) over (-3, 2) to (x, y)

-3 = (-2 + x)/2

-6 = -2 + x

x = -4

2 = (1 + y)/2

4 = 1 + y

y = 3

5 0
2 years ago
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