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Alenkinab [10]
4 years ago
13

In open addressing with linear probing we must consider how to encode

Computers and Technology
1 answer:
matrenka [14]4 years ago
8 0

Answer: B)Available positions

Explanation:Open addressing is the addressing method for the components that are present in the hash table. collision are controlled and managed by this process. The total count of keys is less or equal to the size of table.

Linear probing is the mechanism that helps in controlling of the collision happening by the process of key collection maintenance by encoding of the available positions of the element in the hash table.So,the correct option is option(B).

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Your server runs in quadruple-channel memory mode. How many memory controllers are being used?.
likoan [24]

Answer: four (4)

Explanation:

Quadruple means 4.

7 0
1 year ago
The _______ "represents a set of features that enables the user to inform himself whether a security feature is in operation or
quester [9]

Answer:

Visibility and configuration of security.

Explanation:

The visibility and configuration of security represents a set of features that enables the user to inform himself whether a security feature is in operation or not and whether the use and provision of services should depend on the security feature.

4 0
4 years ago
How many bits can a memory chip with the below configuration support? For full credit, show how you got the answer.
tatiyna

Answer:

Total Memory= 4 KB = 4096 bytes = 32768 bits

Explanation:

<em><u>1. Data lines are 8 From D0 to D7</u></em>

so

Total memory at single address locations is 8 bits.

<em><u>2. Address lines are 12 (A0 to A11)</u></em>

There are 12 address lines but 3 out 12 are for selction of chip or memory bank.

so only 9 pins are there to address the locations on one chip.

Total No. of address locations on single chip = 2^9 = 512 locations

as 1 location is 1 byte so total memory of single chip is 512 bytes.

<u><em>3. Total Memory Bank </em></u>

There are total 3 selection pins for memory bank.

so

Total chips = 2^3 = 8.

<em><u>4. Total Memory </u></em>

Total size of 1 chip = 512 bytes

Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb

<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>

5 0
3 years ago
All of these valid ways to earn money in microworkers except
vovikov84 [41]

Answer:

yes u are trus

Explanation:

mark me as brainliest hehe

8 0
3 years ago
Do you believe that oop should be phased out and we should start working on some alternative?
Ksju [112]
I don’t think we should because we all have our one choices that we should achieved and we should show
5 0
3 years ago
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