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drek231 [11]
3 years ago
7

How to do I don't know how to do can u help me pls. Thanks you

Mathematics
2 answers:
melomori [17]3 years ago
4 0
Alright.
So, we have 2185 student in Rose.
Lily School has 307 more students than Rose, so Lily has,
2185 + 307 = 2492 Students in Lily School.
Since question a. is asking you to round off to the nearest ten, your answer to part a is 2490.

For part b. add 2185 and 2490.
2185 + 2490 = 4675 students. 
The questions want you to round to the nearest hundredth, so,
4700 is the answer to part b.
Degger [83]3 years ago
3 0
You work these problems by first reading and understanding what they are telling you. You are expected to be able to comprehend written English to that extent.

For simplicity, let L and R represent the numbers of students in Lily school and Rose school, respectively. The first sentence tells you
.. R = 2185
The second sentence tells you
.. R = L - 307

a) This question asks you the value of L. Use the given information to find it.
.. 2185 = L -307
.. 2185 +307 = L
.. 2492 = L
You are asked to round this number to the nearest 10. This means you look at the 1s digit (2) and decide if it is 5 or more (it is not). If it is, you add 1 to the tens digit (here, you don't) and then report the number with the 1s digit made zero:
.. There are 2490 pupils in Lily school.


b) This question asks you the total number in both schools. That will be
.. L +R = 2492 +2185 = 4677
You are asked to round this number to the nearest 100. This means you look at the 10s digit (7) and decide if it is 5 or more (it is). If it is, you add 1 to the hundreds digit (here, you do) and then report the number with the 10s and 1s digits made zero:
.. There are 4700 pupils total in the two schools.
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Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

a_n = a_1 + d(n-1)

Plug in a_1 = 4, \ d = 8, \ n = 10 and you should get the following:

a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\

The tenth term is <u>76</u>

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}

---------

In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in a_n = a_1 + d(n-1) which shifts everything one spot to the left.

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