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Korvikt [17]
3 years ago
9

PLEASE HELP ME I"M STUCK! I"LL OFFER BRAINLIEST!! ANY ABSURD ANSWERS WILL BE REPORTED!!

Mathematics
1 answer:
ycow [4]3 years ago
3 0

Answer:

C. This was hard to do when I had this question

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8 There are a combined 33 students who play a spring sport of track or
Rzqust [24]

The number of students that are on the track team are 18.

The number of students that are on the baseball team are 15.

<h3>What are the linear equations that represent the question?</h3>

a + b = 33 equation 1

a - b = 3 equation 2

Where:

  • a = number of students that are on the track team
  • b = number of students that are on the baseball team

<h3>How many students that are on the baseball team?</h3>

Subtract equation 2 from equation 1

2b = 30

Divide both sides by 2

b = 30/2 = 15

<h3>How many students that are on the track team?</h3>

Subtract 15 from 33: 33 - 15 = 18

To learn more about simultaneous equations, please check: brainly.com/question/25875552

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8 0
2 years ago
The image is located at the bottom of the screen.
Setler79 [48]

Answer:

..... surface area = 16 km^2.

7 0
3 years ago
A principal gathered data about the distance in miles that his teachers and bus drivers live from the school
wel

Answer:

<em>The measure distances for the bus drivers is 5 miles less than that of distances for the teachers</em>

Step-by-step explanation:

<em>The range of the distance for the bus drivers live from school with that of the teachers is estimated to be 5 miles apart</em>

<em>The data that was generated in the school by the principal did an estimation of the distances of both the bus driver and that of the teachers, it was found out that the distances was five miles. </em>

4 0
3 years ago
Clarence has already taken 15 pages of notes on his own, and he will take 5 pages during each hour of class. In all, how many ho
horrorfan [7]

Answer:

60-15/2=9

Step-by-step explanation:


7 0
4 years ago
Estimate the diameter of the supergiant star Betelgeuse, using its angular diameter of about 0.05 arcsecond and distance of abou
8090 [49]

<span>0.05 arc-second = 1 degree/72000 = (pi radians)/(180*72000) = 2.424 x 10^(-7) radians</span>

<span>The distance is roughly: </span>

<span>R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275 light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.</span>

7 0
3 years ago
Read 2 more answers
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