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Salsk061 [2.6K]
4 years ago
5

HELP ME PLEASE IM DUMB

Mathematics
1 answer:
Oliga [24]4 years ago
7 0

If Ben reads 8 pages in 12 minutes, we can write it like this 8pages/12minutes.

If you want to know how many he reads in one minute, divide both values with 12, because we know for 12 minutes how many pages he reads, so:

8/12 pages per 12/12minutes = 2/3 of a page per minute.

Hope this helps!

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7^2•3^2+(1+2)^0•3-4^2•1
Kamila [148]
<span>7^2•3^2+(1+2)^0•3-4^2•1
= 49</span>•9 + 1•3 - 16<span>•1
= 441 + 3 - 16
= 428</span>
6 0
3 years ago
What is the GCF of 28a^3 b and 16ab ? <br><br> A)4ab<br> B)4a3b<br> C)28ab<br> D)112a3b2
N76 [4]
28a⁴b: 2 · 2 · 7 · a · a · a · a · b
 16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.
7 0
4 years ago
In a school 40% are boys and 900 are girls. find the total number of students of the school and the number of boys
My name is Ann [436]

Answer:

1500 students

600 boys

Step-by-step explanation:

40% are boys, so 60% are girls.

Writing a proportion:

900 / 60% = x / 100%

x = 1500

There are 1500 students in the school, which means there are 600 boys in the school.

6 0
4 years ago
A local pizzeria offers 15 toppings for their pizzas and you can choose any 3 of them for one fixed price. How many different ty
Shtirlitz [24]

Answer:

  455 or 680, depending

Step-by-step explanation:

If we assume the three choices are different, then there are ...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to make the pizza.

___

If two or three of the topping choices can be the same, then there are an additional ...

  2(15C2) +15C1 = 2·105 +15 = 225

ways to make the pizza, for a total of ...

  455 + 225 = 680

different types of pizza.

__

There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.

_____

nCk = n!/(k!(n-k)!)

6 0
4 years ago
Helppp meee plssss
Volgvan

Answer:

  • Cost of fish = Php. 60, amount of fish = x kg
  • Cost of chicken = Php. 120, amount of chicken = y kg
  • Budget = at most Php. 1200

a) <u>Required inequality (not a system as only one condition is given):</u>

  • 60x + 120y ≤ 1200

<u>Simplified:</u>

  • x + 2y ≤ 20
  • <em>The graph is attached</em>

b) <u>Verify ordered pair (10, 7):</u>

  • 10 + 2*7 ≤ 20
  • 24 ≤ 20

False inequality, so this pair is out of solution set

8 0
3 years ago
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