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Feliz [49]
2 years ago
9

Allison owns a food truck that sells tacos and burritos. She only has enough ingredients to make 98 tacos or burritos.Write an i

nequality that could represent the possible values for the number of tacos sold, tt, and the number of burritos sold, bb, that would satisfy the constraint
Mathematics
1 answer:
leonid [27]2 years ago
7 0

Answer:

98=49bb+49tt

Explain:

so u have the same amount of both

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-18=2+5x solve for x
Korvikt [17]

Answer:

x=-4

Step-by-step explanation:

-18=2+5x

Subtract 2 from both sides

-20=5x

-4=x

3 0
2 years ago
Read 2 more answers
The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th
vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by P(t)=1.394(1.006)^t

To find the derivative you need to:

\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t

To find the population growing at the start of 2014 we say t = 0

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year

To find the population growing at the start of 2015 we say t = 1

P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year

To convert billion to million you multiple by 1000

P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year

6 0
2 years ago
When jack���s puppy was born, she weighed 1.2 pounds. in 2 months, she weighed 11.15 pounds. how much weight did jack���s puppy
NemiM [27]
She gained 9.95 pounds 
6 0
3 years ago
The scale of a model is 0.5in : 6 ft. find the length of the model for an actual length of 204 ft
NNADVOKAT [17]

Answer:

17 in

Step-by-step explanation:

.5 in : 6 ft

204/6 x .5 = 17

8 0
2 years ago
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Naddik [55]
The answer is b I think
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