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3 years ago

Rewrite 11/15 as a decimal number. Round to the nearest thousandth. 1.363 1.364 0.733 0.734

1 answer:

5 0

The answer would be C) 0.733 because divide 11 and 15 and you get 0.733333 and since you wanted it rounded to nearest thousandth, its going to be 3 decimal spaces so remove the last three number 3's from the right and you end up with 0.733.

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The recursive formula for an arithmetic sequence is:

gogolik [260]

the answer should be B-4

3 0

2 years ago

E<img src="https://tex.z-dn.net/?f=e%5E%7Bx%7D%20-%20e%5E%7B-2%7D%20%3D-2" id="TexFormula1" title="e^{x} - e^{-2} =-2" alt="e^{x

pav-90 [236]

$e\cdot e^x -e^{-2}=-2$

$\implies e^{x+1}=e^{-2}-2$

note that RHS is negative. (because e with negative exponent is less than 1)

and LHS is always positive.

so there cannot be any solution

3 0

3 years ago

Triangle DEF has vertices located at D (2, 1), E (3,5), and F (6,2).

IRINA_888 [86]

Answer:

(A)

Length of DE = √17

EF = √18

DF = √17

(B) Slope of DE = 4

EF = 1

DF = 1/4

Step-by-step explanation:

See attached image.

3 0

3 years ago

Factor the expression completely over the complex numbers.<br><br> y^4+12y^2+36

Brums [2.3K]

Y⁴ + 12y² + 36
Now factorize the expression
y⁴ + 6y² + 6y² + 36
= y²(y² + 6) + 6(y² + 6)
= (y² + 6) (y² + 6)
<span>Now 6 is not the perfect square and according to rule, binomial can not be factored as the difference of two perfect squares.
</span>so multiply both.
(y² + 6)² is the answer.

7 0

3 years ago

Read 2 more answers

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

3 years ago