#sol1
a1=1×4-1=3
a2=2×4-1=7
a3=3×4-1=11
a4=4×4-1=15
a5=5×5-1=19
#sol2
f(1)=1×4-1=3,
f(n+1)=f(n)+4,
so .... you know.
Answer:
9 value is ====*0.9*
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Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
If 1/6 of the pan was left and there were 2 pieces left you just need to set 1/6 equal to 2/some number, this allows you to say that 1/6=2/x --> x/6=2-->x=12.
My explanation might be a little poor since this becomes fairly fundamental later on but hopefully it helps.
Answer:
im not sure?
Step-by-step explanation:
