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3 years ago

80% of what how many games is 32 games?

Mathematics

1 answer:

Talja [164]3 years ago

6 0

40 games would be 100% if 32 games is 80%

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Solve my question please, I’ll mark u as brainlest if the answer is correct and if you solved my question!!!

ikadub [295]

Answer:

x = price of balcony tickets = $7

y = price of orchestra tickets = $21

Step-by-step explanation:

Let

x = price of balcony tickets

y = price of orchestra tickets

y = 3x (1)

148y + 76x = 3,640 (2)

Substitute y = 3x into (2)

148y + 76x = 3,640 (2)

148(3x) + 76x = 3,640

444x + 76x = 3,640

520x = 3,640

x = 3,640/520

x = 7

Substitute x = 7 into (1)

y = 3x (1)

y = 3(7)

y = 21

x = price of balcony tickets = $7

y = price of orchestra tickets = $21

3 0

3 years ago

Which of the following could be true if y ≤ -75?

Charra [1.4K]

Answer:-74

Step-by-step explanation: When you are in the megatives, less is more! So -74 is actually greater then -75

6 0

3 years ago

4. 9d - 5 = 4 What does d = 5. 6-3w=-27 what does w = 6. -4= q/8-19 what does q =

trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

4) $9d - 5 = 4$

Adding 5 on both the sides ,

$= > 9d - 5 + 5 = 4 + 5$

$= > 9d = 9$

Dividing both the sides by 9 ,

$= > \frac{9d}{9} = \frac{9}{9}$

$= > d = 1$

5) $6 - 3w = - 27$

Substracting 6 from both the sides ,

$6 - 3w - 6 = - 27 - 6$

$= > - 3w = - 33$

Dividing both the sides by -3 ,

$= > \frac{ - 3w}{ - 3} = \frac{ - 33}{ - 3}$

$= > w = 11$

6) $- 4 = \frac{q}{8} - 19$

Adding 19 on both the sides ,

$\frac{q}{8} - 19 + 19 = - 4 + 19$

$= > \frac{q}{8} = 15$

Multiplying both the sides by 8 ,

$= > \frac{q}{8} \times 8 = 15 \times 8$

$= > q = 120$

6 0

3 years ago

Which of the following is a conjugate for 7 + i Square root of 2? (2 points) − 7 + i Square root of 2 7 − i Square root of 2 i S

hammer [34]

Answer:

$7-\sqrt{2}i$

Step-by-step explanation:

Given number is $7+\sqrt{2}i$ . We need to find the complex conjugate of the given number.

We will use the general rule to find out the complex conjugate of the number.

The complex conjugate of $a+bi$ will be $a-bi$

And the complex conjugate of $7+\sqrt{2}i\ became\ 7-\sqrt{2}i$

So, the complex conjugate of $7+\sqrt{2}i$ is $7-\sqrt{2}i$

3 0

4 years ago

Again the auction house raffle sold 200 tickets at $1 each. How many prizes of $10 should they to make the raffle a fair game?

jekas [21]

200; $1e\pp

they should sell 20 prizes

20x10=200

5 0

3 years ago

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