Answer:
The rhombus ABCD has an area of 22 square units.
Step-by-step explanation:
The coordinates of rhombus ABCD are shown in the image attached below. The area of the rhombus can be found in terms of their diagonals, which are now calculated by Pythagorean Theorem:
![AC = \sqrt{[6-(-4)]^{2}+[8-(-4)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%20%5Csqrt%7B%5B6-%28-4%29%5D%5E%7B2%7D%2B%5B8-%28-4%29%5D%5E%7B2%7D%7D)

![BD = \sqrt{(4-6)^{2}+[0-(-2)]^{2}}](https://tex.z-dn.net/?f=BD%20%3D%20%5Csqrt%7B%284-6%29%5E%7B2%7D%2B%5B0-%28-2%29%5D%5E%7B2%7D%7D)

The area of the rhombus is: (
and
)



The rhombus ABCD has an area of 22 square units.
.25 lbs= 4oz
4oz = 113.398 g
1g= 100cg
113.398 x 100
= 11339. 8 cg
It is the first one, (x,y) to (-x,y) because it is going across the y axis from the positive side, so y stays the same but x becomes negative
It’s “C” I got it right when I had this question before
Answer:
6.18%
Step-by-step explanation: