Tree C is the proper tree. The first game has the possibility of a win, a loss, or a tie which the first row represents. The second game could also win, lose or tie, meaning each result would have each possibilty for that game.
Answer:
no
Step-by-step explanation:
Let f represent the fraction of C-14 remaining as a function of the time t in years. Since the half-life of C-14 is about 5570 years, we have ...
f = (1/2)^(t/5570)
Taking the log and solving for t, we get ...
log(f) = (t/5570)log(1/2)
5570·log(f)/log(1/2) = t
Filling in the given value for f, the value of t we get is ...
5570·log(0.65)/log(0.5) = t ≈ 3462
It appears the estimate of 4000 years is a bit high.
Answer:
(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)
Step-by-step explanation:
we have
----> equation A
-----> equation B
solve by substitution
substitute equation B in equation A
solve for x
<em>Find the value of y</em>
For 
----> 
For 
----> 
therefore
The solutions are
(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)
Answer:
-10
Step-by-step explanation:
-2 + ? = -12
+2 +2
?= -10
