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yan [13]
3 years ago
9

HELP ASAP Linear Equations

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

I and IV only

Step-by-step explanation:

In order for graphs to be parallel, they must have the same slope

In this case, we are looking for a slope of -2/3

We can find the other slopes by solving for y (y=mx+b)

I. 2x+3y=10

Subtract 2x from both sides

3y=-2x+10

Divide by 3

y=-2/3+10/3 This works since the slope is identical

II. 2x-3y=9

Follow a similar progression as the previous (subtract the x's and divide the y's)

-3y=-2x+9

y=2/3=3 This doesn't work since it is positive

III. 4x-6y=30

-6y=-4x+30

y=2/3 x-5 (4/6 simplified to 2/3) Also doesn't work since it is positive

IV. 4x+6y=3

6y=-4x+3

y=-2/3x+3 (-4/6 simplified to -2/3) This one works, it is identical

Scilla [17]3 years ago
4 0

Answer:

4th choice: I and IV only

Step-by-step explanation:

Change the form of the given equation to standard form.

y = -2/3 x + 2

3y = -2x + 6

2x + 3y = 6

Now compare this equation with the 4 choices.

Any equation that has the same x- and y-terms but a different constant term is parallel.

I. is parallel.

II. and III. are not parallel.

Look at IV.:

4x + 6y = 3

Divide both sides by 2:

2x + 3y = 3/2

IV. is also parallel.

Answer: 4th choice: I and IV only

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Answer:

A  = 57°

B = 19°

C = 104°

Step-by-step explanation:

We have a triangle with 3 angles:

A, B, and C.

We know that:

"Angle A is 3 times larger than angle B"

We can write this as:

A = 3*B

"Angle C was 10° less than 6 times angle B"

This can be written as:

C = 6*B - 10°

And we also know that the sum of all interior angles of a triangle is 180°

Then we also have the equation:

A + B + C = 180°

So we have a system of 3 equations:

A = 3*B

C = 6*B - 10°

A + B + C = 180°

To solve this, the first step is to isolate one of the variables in one of the equations.

We can see that A is already isolated in the first one, so we can skip that step.

Now we need to replace A in the other equations, to get:

C = 6*B - 10°

(3*B) + B + C = 180°

Now we have a system of two equations.

Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:

3*B + B + (6*B - 10°) = 180°

Now we can solve this for angle B

4*B + 6*B - 10° = 180°

10*B - 10° = 180°

10*B = 180° + 10° = 190°

B = 190°/10 = 19°

Now that we know the measure of angle B, we can input this in the equations:

A = 3*B

C = 6*B - 10°

To find the measures of the other two angles:

A = 3*19° = 57°

C = 6*19° - 10° = 104°

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Step-by-step explanation:

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$

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Balance on income statements. 226,000

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3 years ago
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