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3 years ago

HELP ASAP Linear Equations

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

5 0

Answer:

I and IV only

Step-by-step explanation:

In order for graphs to be parallel, they must have the same slope

In this case, we are looking for a slope of -2/3

We can find the other slopes by solving for y (y=mx+b)

I. 2x+3y=10

Subtract 2x from both sides

3y=-2x+10

Divide by 3

y=-2/3+10/3 This works since the slope is identical

II. 2x-3y=9

Follow a similar progression as the previous (subtract the x's and divide the y's)

-3y=-2x+9

y=2/3=3 This doesn't work since it is positive

III. 4x-6y=30

-6y=-4x+30

y=2/3 x-5 (4/6 simplified to 2/3) Also doesn't work since it is positive

IV. 4x+6y=3

6y=-4x+3

y=-2/3x+3 (-4/6 simplified to -2/3) This one works, it is identical

Scilla [17]3 years ago

4 0

Answer:

4th choice: I and IV only

Step-by-step explanation:

Change the form of the given equation to standard form.

y = -2/3 x + 2

3y = -2x + 6

2x + 3y = 6

Now compare this equation with the 4 choices.

Any equation that has the same x- and y-terms but a different constant term is parallel.

I. is parallel.

II. and III. are not parallel.

Look at IV.:

4x + 6y = 3

Divide both sides by 2:

2x + 3y = 3/2

IV. is also parallel.

Answer: 4th choice: I and IV only

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Answer:

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we know that

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3 years ago

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Answer:

Step-by-step explanation:

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