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3 years ago

Given f(x) =5 - 3x, if f(x) = -19, find x

Mathematics

1 answer:

ASHA 777 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

5-3(-19)

-3(-19)= 57

57+5=62

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Need help in this ASAP

Artemon [7]

Answer:

The m∠YXW is 125°.

Addition equation: m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°

Step-by-step explanation:

To find the m∠YXW you would need to add the m∠YXZ and m∠ZXW together:

m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°

4 0

3 years ago

Scientists measure a bacteria population and find that it has 10,000 organisms. Five days later, they find that the population h

liraira [26]

Answer:

f(x)= 10,000(2)^x

Step-by-step explanation:

Exponential equations can be modeled by a(r)^x where a is the initial amount, r is the difference, and x is how many units the equation should be squared by.

7 0

2 years ago

Solve the equation -x/6greaterthanequalto3

enot [183]

Answer (depending if the fraction is positive or negative):

x ≥ 18
x ≤ -18

Step-by-step explanation:

If the fraction is positive:

Write it out: $\frac{x}{6} \geq 3$
Multiply each side by 6 to cancel out the 6 under x. It should now look like this: x ≥ 18

If the fraction is negative:

Write it out: $-\frac{x}{6} \geq 3$
Multiply each side by -6 to cancel out the -6 under x. It should now look like this: x ≤ -18

I hope this helps!

3 0

3 years ago

Katrina is reading a book that is 400 pages long. She has read 340 pages so far.

Svetach [21]

$\frac{340}{400}=\frac{340 \div 4}{400 \div 4}=\frac{85}{100}=85\%$

Katrina has read 85% of her book.

7 0

3 years ago

A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?

allsm [11]

Initial velocity=u=0m/s
Distance=s=150m
Time=t=10s
Acceleration=a

Using second equation of kinematics

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2$

$\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a$

$\\ \sf\longmapsto 50a=150$

$\\ \sf\longmapsto a=\dfrac{150}{50}$

$\\ \sf\longmapsto a=3m/s^2$

Mass=m=1000kg
Force=F

Using newtons second law

$\\ \sf\longmapsto F=ma$

$\\ \sf\longmapsto F=1000(3)$

$\\ \sf\longmapsto F=3000N$

3 0

2 years ago